Chapter 12: Surface Areas and Volumes — Online MCQ Test
MATHS · CLASS 10 · Andhra State Board
Practice Chapter 12: Surface Areas and Volumes with a free chapter-wise online MCQ test.
This chapter covers: Cube Cuboid Cylinder Cone Sphere Hemisphere Frustum Surface area Curved surface area Volume Combination of solids.
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter 12: Surface Areas and Volumes — Important Questions & Answers
The curved surface area of a right circular cylinder of radius r and height h is:
- A. 2πrh
- B. πr²h
- C. 2πr(h + r)
- D. πrl
Answer: A. 2πrh
The curved surface area of a cylinder is the area of its rectangular curved part, which is 2πrh.
The curved surface area of a cylinder is the area of its rectangular curved part, which is 2πrh.
The volume of a sphere of radius r is:
- A. 4πr²
- B. (4/3)πr³
- C. (2/3)πr³
- D. πr²h
Answer: B. (4/3)πr³
The standard formula for the volume of a sphere is (4/3)πr³.
The standard formula for the volume of a sphere is (4/3)πr³.
A cylindrical tank has radius 3 m and height 7 m. Its volume is, taking π = 22/7:
- A. 198 m³
- B. 154 m³
- C. 132 m³
- D. 231 m³
Answer: A. 198 m³
Volume of a cylinder = πr²h = (22/7) × 3² × 7 = 198 m³.
Volume of a cylinder = πr²h = (22/7) × 3² × 7 = 198 m³.
A solid is made by placing a hemisphere on a cylinder of the same radius. If the radius is 7 cm and the height of the cylinder is 10 cm, the total surface area of the solid is, taking π = 22/7:
- A. 902 cm²
- B. 748 cm²
- C. 1056 cm²
- D. 594 cm²
Answer: A. 902 cm²
Exposed area = CSA of cylinder + CSA of hemisphere + base of cylinder = 2πrh + 2πr² + πr² = 902 cm².
Exposed area = CSA of cylinder + CSA of hemisphere + base of cylinder = 2πrh + 2πr² + πr² = 902 cm².
A metallic cone of radius 6 cm and height 8 cm is melted and recast into small spheres each of radius 1 cm. The number of spheres formed is:
- A. 64
- B. 72
- C. 84
- D. 96
Answer: B. 72
Volume of cone = (1/3)π × 6² × 8 = 96π. Volume of one sphere = (4/3)π, so number = 96π ÷ (4π/3) = 72.
Volume of cone = (1/3)π × 6² × 8 = 96π. Volume of one sphere = (4/3)π, so number = 96π ÷ (4π/3) = 72.