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Chapter 9: Light Reflection and Refraction — Online MCQ Test

SCIENCE · CLASS 10 · Andhra State Board
Practice Chapter 9: Light Reflection and Refraction with a free chapter-wise online MCQ test. This chapter covers: Reflection Refraction Mirror Lens Image formation Focal length Principal axis Magnification Mirror formula Lens formula Refractive index. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 9: Light Reflection and Refraction — Important Questions & Answers

Which of the following is a law of reflection of light?
  • A. The angle of incidence is equal to the angle of reflection
  • B. The angle of incidence is always greater than the angle of reflection
  • C. The reflected ray always bends towards the normal
  • D. The incident ray and reflected ray are always perpendicular
Answer: A. The angle of incidence is equal to the angle of reflection
According to the laws of reflection, the angle of incidence is equal to the angle of reflection. Also, the incident ray, reflected ray and normal lie in the same plane.
The principal focus of a concave mirror is the point where rays parallel to the principal axis:
  • A. appear to diverge from after reflection
  • B. meet after reflection
  • C. meet after refraction
  • D. remain undeviated
Answer: B. meet after reflection
A concave mirror is a converging mirror. Parallel rays of light actually meet at its principal focus after reflection.
An object is placed beyond the centre of curvature of a concave mirror. The image formed is:
  • A. between the focus and centre of curvature, real, inverted and diminished
  • B. behind the mirror, virtual, erect and enlarged
  • C. at the focus, real, inverted and highly enlarged
  • D. at the pole, virtual and diminished
Answer: A. between the focus and centre of curvature, real, inverted and diminished
For a concave mirror, when the object is beyond C, the image is formed between F and C. It is real, inverted and diminished.
A concave mirror of focal length 10 cm has an object placed 15 cm in front of it. The image formed is:
  • A. real, inverted and magnified two times
  • B. virtual, erect and magnified two times
  • C. real, inverted and diminished
  • D. virtual, erect and diminished
Answer: A. real, inverted and magnified two times
Using f = -10 cm and u = -15 cm in the mirror formula gives v = -30 cm. Magnification m = -v/u = -2, so the image is real, inverted and twice the size.
A convex lens of focal length 20 cm forms a virtual, erect image magnified 3 times. According to the lens formula, the object distance is approximately:
  • A. -13.3 cm
  • B. -20 cm
  • C. -30 cm
  • D. +13.3 cm
Answer: A. -13.3 cm
For a virtual erect image by a convex lens, m = v/u = +3, so v = 3u. Using 1/f = 1/v - 1/u with f = +20 cm gives u = -13.3 cm approximately.