Chapter-4 Laws of Motion — Online MCQ Test
PHYSICS · CLASS 11 INTER I YEAR · Andhra State Board
Practice Chapter-4 Laws of Motion with a free chapter-wise online MCQ test.
This chapter covers: Intuitive concept of force - Inertia - Newton's first law - Momentum - Newton's second law - Impulse - Newton's third law - Law of conservation of linear momentum - Equilibrium of....
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-4 Laws of Motion — Important Questions & Answers
What is the SI unit of force according to Newton's laws of motion?
- A. Dyne
- B. Newton
- C. Kilogram
- D. Joule
Answer: B. Newton
The SI unit of force is Newton (N), defined as the force required to accelerate 1 kg mass at 1 m/s².
The SI unit of force is Newton (N), defined as the force required to accelerate 1 kg mass at 1 m/s².
Which statement best defines inertia?
- A. The tendency of an object to resist changes in its state of motion
- B. The force acting on an object
- C. The rate of change of momentum
- D. The gravitational force on an object
Answer: A. The tendency of an object to resist changes in its state of motion
Inertia is the natural property of matter to resist any change in its state of rest or uniform motion, as stated in Newton's first law.
Inertia is the natural property of matter to resist any change in its state of rest or uniform motion, as stated in Newton's first law.
A block is placed on an inclined plane. The normal force acting on the block is:
- A. Equal to the weight of the block
- B. Equal to the component of weight perpendicular to the plane
- C. Equal to the component of weight parallel to the plane
- D. Always zero
Answer: B. Equal to the component of weight perpendicular to the plane
The normal force equals the component of weight perpendicular to the inclined plane surface, which is mg cos(θ).
The normal force equals the component of weight perpendicular to the inclined plane surface, which is mg cos(θ).
A car of mass 1500 kg is moving in a circular path of radius 50 m at a constant speed of 20 m/s. Calculate the centripetal force required.
- A. 6000 N
- B. 12000 N
- C. 24000 N
- D. 48000 N
Answer: B. 12000 N
Centripetal force = mv²/r = (1500 × 20²)/50 = (1500 × 400)/50 = 12000 N.
Centripetal force = mv²/r = (1500 × 20²)/50 = (1500 × 400)/50 = 12000 N.
A block of mass 10 kg is pulled horizontally on a surface with coefficient of kinetic friction 0.1. If the applied force is 15 N and g = 10 m/s², what is the maximum static friction force that could prevent motion if the block were at rest?
- A. Exactly 15 N
- B. More than 15 N (depends on μs)
- C. Exactly 10 N
- D. Cannot be determined without knowing μs
Answer: D. Cannot be determined without knowing μs
The coefficient of static friction (μs) is different from kinetic friction (μk = 0.1). Maximum static friction = μs × N = μs × 100, which cannot be determined without μs.
The coefficient of static friction (μs) is different from kinetic friction (μk = 0.1). Maximum static friction = μs × N = μs × 100, which cannot be determined without μs.