Chapter 14: Probability — Online MCQ Test
MATHS · Grade 10 · CBSE(NCERT)
Practice Chapter 14: Probability with a free chapter-wise online MCQ test.
This chapter covers: Random experiment Sample space Event Outcomes Classical probability Equally likely events Complementary events Theoretical probability.
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Chapter 14: Probability — Important Questions & Answers
A random experiment is an experiment in which:
- A. the result is known before performing it
- B. there is only one possible outcome
- C. the exact outcome cannot be predicted in advance
- D. the outcome is always favourable
Answer: C. the exact outcome cannot be predicted in advance
In a random experiment, we know the possible outcomes but cannot predict the exact outcome before performing it.
In a random experiment, we know the possible outcomes but cannot predict the exact outcome before performing it.
If a coin is tossed once, the sample space is:
- A. {H}
- B. {T}
- C. {H, T}
- D. {HH, TT}
Answer: C. {H, T}
A single coin toss can result in either Head or Tail, so the sample space is {H, T}.
A single coin toss can result in either Head or Tail, so the sample space is {H, T}.
A fair die is thrown once. What is the probability of getting an even number?
- A. 1/6
- B. 1/3
- C. 1/2
- D. 2/3
Answer: C. 1/2
The even numbers on a die are 2, 4 and 6. Thus, probability = 3/6 = 1/2.
The even numbers on a die are 2, 4 and 6. Thus, probability = 3/6 = 1/2.
A fair die is thrown once. What is the probability of getting a number which is either even or prime?
- A. 1/3
- B. 1/2
- C. 5/6
- D. 2/3
Answer: C. 5/6
Even numbers are 2, 4, 6 and prime numbers are 2, 3, 5. The favourable outcomes are 2, 3, 4, 5, 6, so probability = 5/6.
Even numbers are 2, 4, 6 and prime numbers are 2, 3, 5. The favourable outcomes are 2, 3, 4, 5, 6, so probability = 5/6.
Two dice are thrown together. What is the probability of getting a doublet or a sum of 8?
- A. 1/4
- B. 5/18
- C. 11/36
- D. 1/3
Answer: B. 5/18
There are 6 doublets and 5 outcomes with sum 8: (2,6), (3,5), (4,4), (5,3), (6,2). Since (4,4) is common, favourable outcomes = 6 + 5 - 1 = 10, so probability = 10/36 = 5/18.
There are 6 doublets and 5 outcomes with sum 8: (2,6), (3,5), (4,4), (5,3), (6,2). Since (4,4) is common, favourable outcomes = 6 + 5 - 1 = 10, so probability = 10/36 = 5/18.