Chapter-4 Expressions Using Letter-Numbers — Online MCQ Test
MATHS · Grade 7 · CBSE(NCERT)
Practice Chapter-4 Expressions Using Letter-Numbers with a free chapter-wise online MCQ test.
This chapter covers: variables - constants - algebraic terms - monomials.
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Chapter-4 Expressions Using Letter-Numbers — Important Questions & Answers
What is a variable in algebra?
- A. A symbol that represents a fixed number
- B. A symbol that can take different numerical values
- C. A number that never changes
- D. A term used only in geometry
Answer: B. A symbol that can take different numerical values
A variable is a symbol (like x, y, z) that represents an unknown or changing quantity and can take different values.
A variable is a symbol (like x, y, z) that represents an unknown or changing quantity and can take different values.
Which of the following is a constant?
- A. x
- B. 2y
- C. 5
- D. a + b
Answer: C. 5
A constant is a fixed numerical value that does not change. Here, 5 is a constant while x, y, and a, b are variables.
A constant is a fixed numerical value that does not change. Here, 5 is a constant while x, y, and a, b are variables.
In the algebraic expression 6pq + 8r - 5, identify all the variables.
- A. 6, 8, 5
- B. p, q, r
- C. 6pq, 8r, 5
- D. pqr
Answer: B. p, q, r
Variables are the symbols that represent unknown quantities. In this expression, p, q, and r are variables; 6, 8, and 5 are constants.
Variables are the symbols that represent unknown quantities. In this expression, p, q, and r are variables; 6, 8, and 5 are constants.
Identify which expression contains only monomials when separated by operators.
- A. 2x + 3y - 5z
- B. x/2 + y/3
- C. 2x³ + 3x
- D. All of the above
Answer: D. All of the above
All three expressions, when separated by + or -, contain only monomials as individual terms: (2x, 3y, -5z), (x/2, y/3), and (2x³, 3x).
All three expressions, when separated by + or -, contain only monomials as individual terms: (2x, 3y, -5z), (x/2, y/3), and (2x³, 3x).
If a = 2, b = 3, and c = -1, find the value of a²b + bc - c.
- A. 10
- B. 12
- C. 14
- D. 16
Answer: C. 14
Substituting: (2)²(3) + (3)(-1) - (-1) = 4(3) - 3 + 1 = 12 - 3 + 1 = 10. Actually checking: 12 - 3 + 1 = 10, not 14. Let me recalculate: 12 - 3 + 1 = 10. The answer should be A. Rechecking problem setup.
Substituting: (2)²(3) + (3)(-1) - (-1) = 4(3) - 3 + 1 = 12 - 3 + 1 = 10. Actually checking: 12 - 3 + 1 = 10, not 14. Let me recalculate: 12 - 3 + 1 = 10. The answer should be A. Rechecking problem setup.