Chapter-6 Number Play — Online MCQ Test
MATHS · Grade 7 · CBSE(NCERT)
Practice Chapter-6 Number Play with a free chapter-wise online MCQ test.
This chapter covers: parity - Fibonacci sequence - cryptarithms - number patterns.
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-6 Number Play — Important Questions & Answers
What is the definition of an even number?
- A. A number divisible by 2
- B. A number divisible by 3
- C. A number greater than 10
- D. A number with two digits
Answer: A. A number divisible by 2
An even number is any integer that can be divided by 2 without a remainder.
An even number is any integer that can be divided by 2 without a remainder.
Which of the following is an odd number?
- A. 24
- B. 35
- C. 42
- D. 50
Answer: B. 35
35 is odd because it leaves a remainder of 1 when divided by 2, unlike 24, 42, and 50 which are all even.
35 is odd because it leaves a remainder of 1 when divided by 2, unlike 24, 42, and 50 which are all even.
What is the sum of an even number and an odd number?
- A. Always even
- B. Always odd
- C. Sometimes even, sometimes odd
- D. Always zero
Answer: B. Always odd
The sum of an even number and an odd number is always odd (e.g., 2 + 3 = 5; 4 + 5 = 9).
The sum of an even number and an odd number is always odd (e.g., 2 + 3 = 5; 4 + 5 = 9).
In the cryptarithm puzzle, if AB + BA = CDC, where A, B, C, D are different digits, which statement must be true?
- A. A + B must be less than 10
- B. A + B must be greater than 10
- C. C must be 1
- D. D must be 0
Answer: C. C must be 1
When two 2-digit numbers add to a 3-digit number, the result must be between 100-198, so C must be 1.
When two 2-digit numbers add to a 3-digit number, the result must be between 100-198, so C must be 1.
In a complex cryptarithm where HE + LOVES = MATH, what is the maximum possible value for the digit represented by M?
- A. 9
- B. 8
- C. 2
- D. 1
Answer: D. 1
Since HE (max 98) + LOVES (max 98765) cannot exceed 99863, M can only be 1 because the sum of a 2-digit and 5-digit number starting with different letters in a cryptarithm context creates a result where M=1.
Since HE (max 98) + LOVES (max 98765) cannot exceed 99863, M can only be 1 because the sum of a 2-digit and 5-digit number starting with different letters in a cryptarithm context creates a result where M=1.