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Chapter-2 Motion — Online MCQ Test

PHYSICS · Grade 10 · IGCSE cambridge
Practice Chapter-2 Motion with a free chapter-wise online MCQ test. This chapter covers: Speed velocity and acceleration interpreting distance-time and speed-time graphs and free fall.. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-2 Motion — Important Questions & Answers

Which of the following is a scalar quantity?
  • A. Velocity
  • B. Displacement
  • C. Speed
  • D. Acceleration
Answer: C. Speed
Speed is a scalar quantity as it only has magnitude and no direction. Velocity, displacement, and acceleration are all vector quantities with both magnitude and direction.
What is the SI unit of acceleration?
  • A. m/s
  • B. m/s²
  • C. km/h
  • D. m
Answer: B. m/s²
The SI unit of acceleration is metres per second squared (m/s²), which represents the change in velocity per unit time.
A distance-time graph shows a straight line with a steep positive slope. What does this indicate?
  • A. The object is at rest
  • B. The object is moving at constant high speed
  • C. The object is decelerating
  • D. The object is accelerating uniformly
Answer: B. The object is moving at constant high speed
A straight line on a distance-time graph indicates constant speed. A steep positive slope indicates the object covers large distances in small time intervals, meaning high constant speed.
A speed-time graph shows a horizontal line at 25 m/s. What can be concluded about the object's motion?
  • A. The object is accelerating uniformly
  • B. The object is moving at constant velocity with zero acceleration
  • C. The object is decelerating
  • D. The object is at rest
Answer: B. The object is moving at constant velocity with zero acceleration
A horizontal line on a speed-time graph indicates constant speed and zero acceleration, meaning the velocity remains unchanged throughout the motion.
A ball is thrown upward with initial velocity 30 m/s. At what time will it return to the same height? (g = 10 m/s²)
  • A. 3 seconds
  • B. 6 seconds
  • C. 9 seconds
  • D. 15 seconds
Answer: B. 6 seconds
Using v = u + at, at maximum height v = 0: t = u/g = 30/10 = 3 s to reach the top. Total time = 2 × 3 = 6 seconds to return to the same height.