Chapter-5 Momentum — Online MCQ Test
PHYSICS · Grade 10 · IGCSE cambridge
Practice Chapter-5 Momentum with a free chapter-wise online MCQ test.
This chapter covers: Momentum impulse and applying conservation of momentum to collisions..
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-5 Momentum — Important Questions & Answers
Momentum is defined as the product of an object's mass and its ________.
- A. acceleration
- B. velocity
- C. force
- D. kinetic energy
Answer: B. velocity
Momentum (p) is calculated as p = m × v, where m is mass and v is velocity. It is a vector quantity with SI unit kg·m/s.
Momentum (p) is calculated as p = m × v, where m is mass and v is velocity. It is a vector quantity with SI unit kg·m/s.
Which of the following is NOT a vector quantity?
- A. Momentum
- B. Velocity
- C. Mass
- D. Force
Answer: C. Mass
Mass is a scalar quantity (has magnitude only). Momentum, velocity, and force are all vector quantities (magnitude and direction).
Mass is a scalar quantity (has magnitude only). Momentum, velocity, and force are all vector quantities (magnitude and direction).
A ball of mass 2 kg experiences a force of 10 N for 4 seconds. What is the impulse imparted to the ball?
- A. 5 N·s
- B. 20 N·s
- C. 40 N·s
- D. 80 N·s
Answer: C. 40 N·s
Impulse J = F × t = 10 N × 4 s = 40 N·s. Impulse equals the change in momentum.
Impulse J = F × t = 10 N × 4 s = 40 N·s. Impulse equals the change in momentum.
A person throws a 0.5 kg ball horizontally with a velocity of 10 m/s while standing on a frictionless surface. The person's mass is 70 kg. What is the recoil velocity of the person?
- A. 0.071 m/s in the opposite direction
- B. 0.14 m/s in the opposite direction
- C. 1.4 m/s in the opposite direction
- D. 7.14 m/s in the opposite direction
Answer: A. 0.071 m/s in the opposite direction
Using conservation of momentum: 0 = (0.5 × 10) + (70 × v). v = -5/70 = -0.071 m/s (opposite direction). The negative sign indicates recoil.
Using conservation of momentum: 0 = (0.5 × 10) + (70 × v). v = -5/70 = -0.071 m/s (opposite direction). The negative sign indicates recoil.
In a collision scenario, which of the following conditions would result in a violation of the law of conservation of momentum?
- A. External friction force acts on the system during collision
- B. The collision is perfectly inelastic
- C. The collision occurs on a smooth horizontal surface
- D. Both objects have the same velocity before collision
Answer: A. External friction force acts on the system during collision
Momentum is conserved only in isolated systems (no external forces). If external friction acts on the system, momentum is not conserved. The nature of collision (elastic/inelastic) doesn't affect momentum conservation.
Momentum is conserved only in isolated systems (no external forces). If external friction acts on the system, momentum is not conserved. The nature of collision (elastic/inelastic) doesn't affect momentum conservation.