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Chapter-3 PAIR OF LINEAR EQUATIONS IN TWO VARIABLES — Online MCQ Test

MATHS · CLASS 10th · Karnataka State Board
Practice Chapter-3 PAIR OF LINEAR EQUATIONS IN TWO VARIABLES with a free chapter-wise online MCQ test. This chapter covers: chapter-3. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-3 PAIR OF LINEAR EQUATIONS IN TWO VARIABLES — Important Questions & Answers

A pair of linear equations in two variables is of the form a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0. What condition must be satisfied for the system to have a unique solution?
  • A. a₁/a₂ = b₁/b₂
  • B. a₁/a₂ ≠ b₁/b₂
  • C. a₁/a₂ = b₁/b₂ = c₁/c₂
  • D. a₁ × a₂ = b₁ × b₂
Answer: B. a₁/a₂ ≠ b₁/b₂
For a unique solution, the lines must intersect at exactly one point, which occurs when a₁/a₂ ≠ b₁/b₂ (the lines are not parallel).
Which of the following is the correct definition of consistent equations?
  • A. Equations that have no solution
  • B. Equations that have at least one solution
  • C. Equations that have exactly two solutions
  • D. Equations that are always contradictory
Answer: B. Equations that have at least one solution
Consistent equations are those that have at least one common solution, either unique or infinitely many.
Solve the system: x + y = 5 and x - y = 3. What is the value of x?
  • A. 1
  • B. 2
  • C. 3
  • D. 4
Answer: D. 4
Adding both equations: 2x = 8, so x = 4. Verification: 4 + 1 = 5 and 4 - 1 = 3 ✓
Analyze the system: 4x + 6y = 8 and 2x + 3y = 4. The nature of this system is:
  • A. Inconsistent (parallel lines)
  • B. Consistent with unique solution
  • C. Consistent with infinitely many solutions
  • D. Degenerate
Answer: C. Consistent with infinitely many solutions
The first equation simplifies to 2x + 3y = 4 when divided by 2, which is identical to the second equation, so infinitely many solutions exist.
If the pair of equations px + qy = m and rx + sy = n represent two perpendicular lines, which statement is always true?
  • A. pr + qs = 0
  • B. p/r = q/s
  • C. ps = qr
  • D. p + r = q + s
Answer: A. pr + qs = 0
For perpendicular lines, the product of their slopes equals -1. The slopes are -p/q and -r/s, so (-p/q)(-r/s) = -1, which simplifies to pr + qs = 0.