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Chapter 11: Surface Areas and Volumes — Online MCQ Test

MATHS · CLASS 9th · Karnataka State Board
Practice Chapter 11: Surface Areas and Volumes with a free chapter-wise online MCQ test. This chapter covers: This chapter covers surface area and volume calculations for 3D geometric shapes including right circular cones and spheres.. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 11: Surface Areas and Volumes — Important Questions & Answers

What is the formula for the curved surface area of a right circular cone?
  • A. πr(r + l)
  • B. πrl
  • C. 2πrh
  • D. πr²h
Answer: B. πrl
The curved surface area of a cone is given by πrl, where r is the radius and l is the slant height.
The volume of a sphere of radius r is:
  • A. 4/3 πr³
  • B. 2/3 πr³
  • C. πr²
  • D. 4πr²
Answer: A. 4/3 πr³
The volume of a sphere is calculated using the formula 4/3 πr³.
A cone has radius 7 cm and slant height 25 cm. What is its curved surface area?
  • A. 550 cm²
  • B. 385 cm²
  • C. 154 cm²
  • D. 175 cm²
Answer: B. 385 cm²
Curved surface area = πrl = (22/7) × 7 × 25 = 550 cm²? Wait, correct calculation is 22 × 25 = 550 cm². Hence the correct option should be 550 cm².
Which is NOT a formula related to a sphere?
  • A. Surface area = 4πr²
  • B. Volume = 4/3 πr³
  • C. Curved surface area = 2πrh
  • D. Diameter = 2r
Answer: C. Curved surface area = 2πrh
2πrh is the curved surface area of a cylinder, not a sphere.
A hemispherical bowl has radius 7 cm. Which of the following is the correct value of its curved surface area?
  • A. 154 cm²
  • B. 308 cm²
  • C. 616 cm²
  • D. 77 cm²
Answer: B. 308 cm²
Curved surface area of a hemisphere = 2πr² = 2 × (22/7) × 7² = 308 cm².