Unit 12: Coordination Compounds — Online MCQ Test
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Practice Unit 12: Coordination Compounds with a free chapter-wise online MCQ test.
This chapter covers: Introduction to coordination compounds. Werner's theory; ligands coordination number denticity. chelation; IUPAC nomenclature of mononuclear co-ordination compounds isomerism; Bond....
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Unit 12: Coordination Compounds — Important Questions & Answers
Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?
- A. SCN- < F- < CN- < C2O4 2-
- B. F- < SCN- < C2O4 2- < CN-
- C. CN- < C2O4 2- < SCN- < F-
- D. SCN- < F- < C2O4 2- < CN-
Answer: D. SCN- < F- < C2O4 2- < CN-
According to the spectrochemical series, the order of increasing field strength for these ligands is SCN- < F- < C2O4 2- < CN-.
According to the spectrochemical series, the order of increasing field strength for these ligands is SCN- < F- < C2O4 2- < CN-.
Which of the following are paramagnetic? A. [NiCl4]²⁻ B. Ni(CO)₄ C. [Ni(CN)₄]²⁻ D. [Ni(H₂O)₆]²⁺ E. Ni(PPh₃)₄
- A. A and C only
- B. B and E only
- C. A and D only
- D. A, D and E only
Answer: C. A and D only
[NiCl₄]²⁻ (sp³) is paramagnetic (2 unpaired e⁻). Ni(CO)₄, [Ni(CN)₄]²⁻, and Ni(PPh₃)₄ are diamagnetic. [Ni(H₂O)₆]²⁺ (sp³d²) is paramagnetic (2 unpaired e⁻).
[NiCl₄]²⁻ (sp³) is paramagnetic (2 unpaired e⁻). Ni(CO)₄, [Ni(CN)₄]²⁻, and Ni(PPh₃)₄ are diamagnetic. [Ni(H₂O)₆]²⁺ (sp³d²) is paramagnetic (2 unpaired e⁻).
The correct order of the wavelength of light absorbed by the following complexes is: A. [Co(NH₃)₆]³⁺ B. [Co(CN)₆]³⁻ C. [Cu(H₂O)₄]²⁺ D. [Ti(H₂O)₆]³⁺
- A. B < D < A < C
- B. B < A < D < C
- C. C < D < A < B
- D. C < A < D < B
Answer: B. B < A < D < C
Wavelength absorbed is inversely proportional to crystal field splitting (Δ). Stronger ligands cause higher splitting, hence lower wavelength absorbed. Order of field strength: CN⁻ > NH₃ > H₂O.
Wavelength absorbed is inversely proportional to crystal field splitting (Δ). Stronger ligands cause higher splitting, hence lower wavelength absorbed. Order of field strength: CN⁻ > NH₃ > H₂O.
Iron carbonyl, Fe(CO)5 is
- A. Tetranuclear
- B. Dinuclear
- C. Trinuclear
- D. Mononuclear
Answer: D. Mononuclear
Fe(CO)5 contains only one iron atom, therefore it is classified as mononuclear.
Fe(CO)5 contains only one iron atom, therefore it is classified as mononuclear.
Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code: Column I: a. Co3+, b. Cr3+, c. Fe3+, d. Ni2+ Column II: i. 8 B.M., ii. 35 B.M., iii. 3 B.M., iv. 24 B.M., v. 15 B.M.
- A. (1) iv v ii i
- B. (2) i ii iii iv
- C. (3) iv i ii iii
- D. (4) iii v i ii
Answer: D. (4) iii v i ii
Spin magnetic moment = sqrt(n(n+2)) BM. Co3+ (3d6, n=4) -> sqrt(24)=4.9, Cr3+ (3d3, n=3) -> sqrt(15)=3.87, Fe3+ (3d5, n=5) -> sqrt(35)=5.9, Ni2+ (3d8, n=2) -> sqrt(8)=2.82. Matches: a-iii, b-v, c-i, d-ii.
Spin magnetic moment = sqrt(n(n+2)) BM. Co3+ (3d6, n=4) -> sqrt(24)=4.9, Cr3+ (3d3, n=3) -> sqrt(15)=3.87, Fe3+ (3d5, n=5) -> sqrt(35)=5.9, Ni2+ (3d8, n=2) -> sqrt(8)=2.82. Matches: a-iii, b-v, c-i, d-ii.