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Chapter 10: Operations Research — Online MCQ Test

BUSINESS MATHS AND STATISTICS · CLASS 11th · Tamil Nadu State Board
Practice Chapter 10: Operations Research with a free chapter-wise online MCQ test. This chapter covers: The final chapter introduces linear programming formulation graphical solution methods and network analysis. Students study project scheduling critical path method CPM and Programm.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 10: Operations Research — Important Questions & Answers

What is the main objective of Operations Research?
  • A. To reduce labour wages
  • B. To provide optimum solution to decision problems
  • C. To increase inventory without limit
  • D. To avoid all mathematical methods
Answer: B. To provide optimum solution to decision problems
Operations Research aims at finding the best or optimum solution under given restrictions and constraints.
In a Linear Programming Problem (LPP), the restrictions on the decision variables are called:
  • A. Objective function
  • B. Constraints
  • C. Slack variables
  • D. Feasible region
Answer: B. Constraints
Constraints are the limitations or conditions imposed on the decision variables in an LPP.
Which of the following is the correct objective function form in an LPP?
  • A. x + y ≥ 10
  • B. 2x + 3y = 12
  • C. Max Z = 5x + 4y
  • D. x, y ≥ 0
Answer: C. Max Z = 5x + 4y
The objective function represents the quantity to be maximized or minimized, such as profit or cost.
The expected time of an activity in PERT is calculated using:
  • A. (a + 4m + b) / 6
  • B. (a + m + b) / 3
  • C. (2a + 3m + b) / 6
  • D. (a + 2m + 3b) / 6
Answer: A. (a + 4m + b) / 6
PERT uses the weighted average formula where the most likely time is given four times the weight.
In PERT, if the optimistic time is 4, the most likely time is 10 and the pessimistic time is 16, what is the expected time?
  • A. 9
  • B. 10
  • C. 11
  • D. 12
Answer: B. 10
Expected time = (a + 4m + b) / 6 = (4 + 4×10 + 16) / 6 = 60/6 = 10.