Chapter 14: Haloalkanes and Haloarenes — Online MCQ Test
CHEMISTRY · CLASS 11th · Tamil Nadu State Board
Practice Chapter 14: Haloalkanes and Haloarenes with a free chapter-wise online MCQ test.
This chapter covers: Focusing on organohalogen compounds this chapter details preparation physical properties and nucleophilic substitution mechanisms SN1 and SN2. Students study haloarene electrophili....
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Chapter 14: Haloalkanes and Haloarenes — Important Questions & Answers
Which of the following reagents is used in the Finkelstein reaction for the preparation of alkyl iodides?
- A. NaI in dry acetone
- B. AgF in water
- C. KI in ethanol
- D. NaCl in ether
Answer: A. NaI in dry acetone
Finkelstein reaction involves the exchange of halogen with iodine using sodium iodide in dry acetone.
Finkelstein reaction involves the exchange of halogen with iodine using sodium iodide in dry acetone.
What is the hybridisation of the carbon atom bonded to the halogen in a haloalkane?
- A. sp
- B. sp2
- C. sp3
- D. dsp2
Answer: C. sp3
In haloalkanes, the carbon atom attached to the halogen is saturated and thus sp3 hybridised.
In haloalkanes, the carbon atom attached to the halogen is saturated and thus sp3 hybridised.
Which mechanism is followed by the reaction of tert-butyl bromide with aqueous KOH?
- A. SN1
- B. SN2
- C. E1
- D. E2
Answer: A. SN1
Tertiary alkyl halides react via the SN1 mechanism due to the formation of a stable carbocation intermediate.
Tertiary alkyl halides react via the SN1 mechanism due to the formation of a stable carbocation intermediate.
Why are aryl halides less reactive towards nucleophilic substitution compared to alkyl halides?
- A. Due to C-Cl bond resonance
- B. Due to steric hindrance
- C. Due to sp3 hybridization
- D. Due to high electronegativity of carbon
Answer: A. Due to C-Cl bond resonance
Partial double bond character due to resonance makes the C-X bond in aryl halides stronger and harder to break.
Partial double bond character due to resonance makes the C-X bond in aryl halides stronger and harder to break.
Which reagent is most effective for converting an alcohol into an alkyl chloride without retention of configuration?
- A. PCl5
- B. SOCl2 in pyridine
- C. HCl/ZnCl2
- D. SOCl2 without pyridine
Answer: D. SOCl2 without pyridine
SOCl2 alone provides alkyl chloride with inversion of configuration, whereas pyridine leads to retention.
SOCl2 alone provides alkyl chloride with inversion of configuration, whereas pyridine leads to retention.