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Chapter 9: Solutions — Online MCQ Test

CHEMISTRY · CLASS 11th · Tamil Nadu State Board
Practice Chapter 9: Solutions with a free chapter-wise online MCQ test. This chapter covers: Focusing on liquid mixtures this chapter details solution types concentration units Raoult law and ideal non-ideal solutions. Students study colligative properties vapor pressure l.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 9: Solutions — Important Questions & Answers

Which concentration unit represents the number of moles of solute per kilogram of solvent?
  • A. Molarity
  • B. Molality
  • C. Normality
  • D. Mole fraction
Answer: B. Molality
Molality is defined as the number of moles of solute dissolved in 1 kg of solvent.
An ideal solution is one that obeys:
  • A. Raoult's law over the entire range of concentration
  • B. Henry's law
  • C. Dalton's law
  • D. None of these
Answer: A. Raoult's law over the entire range of concentration
An ideal solution obeys Raoult's law at all concentrations and temperatures.
In a non-ideal solution, which of the following is true for a positive deviation from Raoult's law?
  • A. ΔHmix = 0
  • B. ΔVmix = 0
  • C. ΔHmix > 0
  • D. A-B interactions are stronger than A-A or B-B
Answer: C. ΔHmix > 0
For positive deviation, intermolecular forces are weaker, leading to endothermic mixing (ΔHmix > 0) and expansion in volume (ΔVmix > 0).
Two liquids A and B form an azeotropic mixture at a specific composition. This means:
  • A. They can be separated by fractional distillation
  • B. They have different boiling points
  • C. They distill at the same temperature without change in composition
  • D. They obey Raoult's law perfectly
Answer: C. They distill at the same temperature without change in composition
Azeotropes are constant boiling mixtures where the liquid and vapor phases have identical compositions.
A solution contains 1 mole of solute A and 3 moles of solvent B. The mole fraction of solute A is:
  • A. 0.75
  • B. 0.25
  • C. 0.33
  • D. 0.20
Answer: B. 0.25
Mole fraction of A = moles of A / (moles of A + moles of B) = 1 / (1 + 3) = 1/4 = 0.25.