Chapter 6: Gravitation — Online MCQ Test
PHYSICS · CLASS 11th · Tamil Nadu State Board
Practice Chapter 6: Gravitation with a free chapter-wise online MCQ test.
This chapter covers: Focusing on celestial mechanics this chapter details Kepler laws Newton law of gravitation gravitational potential energy and field intensity. Students examine acceleration due to....
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Chapter 6: Gravitation — Important Questions & Answers
The constant of proportionality G in Newton's law of gravitation is known as:
- A. Acceleration due to gravity
- B. Universal gravitational constant
- C. Gravitational intensity
- D. Gravitational potential
Answer: B. Universal gravitational constant
G is called the Universal Gravitational Constant with a value of 6.67 x 10^-11 Nm^2/kg^2.
G is called the Universal Gravitational Constant with a value of 6.67 x 10^-11 Nm^2/kg^2.
Which of Kepler's laws is also known as the Law of Periods?
- A. First Law
- B. Second Law
- C. Third Law
- D. None of these
Answer: C. Third Law
Kepler's third law states that the square of the period of revolution is proportional to the cube of the semi-major axis.
Kepler's third law states that the square of the period of revolution is proportional to the cube of the semi-major axis.
If the Earth were to stop rotating, the weight of a body at the equator would:
- A. Increase
- B. Decrease
- C. Remain the same
- D. Become zero
Answer: A. Increase
Weight at the equator is mg - m(omega^2)R; if rotation stops, the centrifugal term becomes zero, increasing effective weight.
Weight at the equator is mg - m(omega^2)R; if rotation stops, the centrifugal term becomes zero, increasing effective weight.
If the mass of the Earth were doubled and its radius halved, the new value of 'g' would be:
- A. 2g
- B. 4g
- C. 8g
- D. g
Answer: C. 8g
g' = G(2M)/(R/2)^2 = 8 * GM/R^2 = 8g.
g' = G(2M)/(R/2)^2 = 8 * GM/R^2 = 8g.
If the distance between the Earth and the Sun were half of its present value, the number of days in a year would be approximately:
- A. 64.5
- B. 129
- C. 182.5
- D. 730
Answer: B. 129
By Kepler's Third Law, T^2 proportional to r^3. T' = T * (1/2)^(3/2) = 365 / 2.828 = 129 days.
By Kepler's Third Law, T^2 proportional to r^3. T' = T * (1/2)^(3/2) = 365 / 2.828 = 129 days.