Chapter-7 Mensuration — Online MCQ Test
MATHS · Samacheer Kalvi 9th · Tamil Nadu State Board
Practice Chapter-7 Mensuration with a free chapter-wise online MCQ test.
This chapter covers: Description Explains surface area and volume of three dimensional solids with practical problems Keywords Surface Area Volume Cube Cuboid Cone Cylinder Sphere.
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-7 Mensuration — Important Questions & Answers
What is the formula for the volume of a cube with side length 'a'?
- A. a²
- B. 4a
- C. a³
- D. 6a²
Answer: C. a³
The volume of a cube is the product of its three equal sides, so it is a × a × a = a³.
The volume of a cube is the product of its three equal sides, so it is a × a × a = a³.
Which of the following is the curved surface area of a cylinder of radius r and height h?
- A. 2πr(h + r)
- B. πr²h
- C. 2πrh
- D. 4πr²
Answer: C. 2πrh
The curved surface area of a cylinder is 2πrh. It does not include the circular bases.
The curved surface area of a cylinder is 2πrh. It does not include the circular bases.
A cuboid has length 8 cm, breadth 5 cm and height 3 cm. What is its volume?
- A. 16 cm³
- B. 40 cm³
- C. 120 cm³
- D. 240 cm³
Answer: C. 120 cm³
Volume of a cuboid = l × b × h = 8 × 5 × 3 = 120 cm³.
Volume of a cuboid = l × b × h = 8 × 5 × 3 = 120 cm³.
A cuboid has dimensions 10 cm × 6 cm × 4 cm. Which expression gives its total surface area?
- A. 2(10 × 6 + 6 × 4 + 4 × 10)
- B. 10 × 6 × 4
- C. 2π(10)(4)
- D. 4π(6)²
Answer: A. 2(10 × 6 + 6 × 4 + 4 × 10)
The total surface area of a cuboid is 2(lb + bh + hl). Substituting the dimensions gives 2(10×6 + 6×4 + 4×10).
The total surface area of a cuboid is 2(lb + bh + hl). Substituting the dimensions gives 2(10×6 + 6×4 + 4×10).
A cylindrical tank has radius 7 m and height 5 m. If it is filled with water up to 2/5 of its capacity, what is the volume of water? (Take π = 22/7)
- A. 154 m³
- B. 308 m³
- C. 77 m³
- D. 220 m³
Answer: A. 154 m³
Full volume of the tank = πr²h = 22/7 × 7² × 5 = 770 m³. Two-fifths of this is 770 × 2/5 = 308 m³, so the correct answer is 308 m³.
Full volume of the tank = πr²h = 22/7 × 7² × 5 = 770 m³. Two-fifths of this is 770 × 2/5 = 308 m³, so the correct answer is 308 m³.