Chapter 10: Mensuration — Online MCQ Test
MATHS · CLASS 10th · Telangana State Board
Practice Chapter 10: Mensuration with a free chapter-wise online MCQ test.
This chapter covers: Extending spatial measurement to three-dimensional geometry.
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter 10: Mensuration — Important Questions & Answers
What is the formula for the volume of a cylinder?
- A. πr²h
- B. 2πrh
- C. πr²
- D. 2πr²h
Answer: A. πr²h
The volume of a cylinder is πr²h, where r is the radius and h is the height. This is the area of the circular base multiplied by the height.
The volume of a cylinder is πr²h, where r is the radius and h is the height. This is the area of the circular base multiplied by the height.
The curved surface area of a cone is given by which formula?
- A. πrl
- B. πr²l
- C. 2πrl
- D. πr(r+l)
Answer: A. πrl
The curved surface area of a cone is πrl, where r is the radius of the base and l is the slant height.
The curved surface area of a cone is πrl, where r is the radius of the base and l is the slant height.
A cylinder has radius 7 cm and height 10 cm. What is its volume? (Use π = 22/7)
- A. 1540 cm³
- B. 1480 cm³
- C. 1620 cm³
- D. 1400 cm³
Answer: A. 1540 cm³
Volume = πr²h = (22/7) × 7² × 10 = (22/7) × 49 × 10 = 22 × 7 × 10 = 1540 cm³.
Volume = πr²h = (22/7) × 7² × 10 = (22/7) × 49 × 10 = 22 × 7 × 10 = 1540 cm³.
A cylindrical tank has radius 5 m and height 7 m. If it is filled with water at ₹50 per cubic meter, what is the total cost? (Use π = 22/7)
- A. ₹27,500
- B. ₹30,500
- C. ₹25,000
- D. ₹35,000
Answer: A. ₹27,500
Volume = πr²h = (22/7) × 5² × 7 = (22/7) × 25 × 7 = 550 m³. Cost = 550 × 50 = ₹27,500.
Volume = πr²h = (22/7) × 5² × 7 = (22/7) × 25 × 7 = 550 m³. Cost = 550 × 50 = ₹27,500.
A cone's base radius is tripled while its height remains constant. By what factor does its volume increase?
- A. 3 times
- B. 6 times
- C. 9 times
- D. 27 times
Answer: C. 9 times
Volume of cone = (1/3)πr²h. If radius becomes 3r, new volume = (1/3)π(3r)²h = (1/3)π(9r²)h = 9 × (1/3)πr²h. So volume increases by 9 times.
Volume of cone = (1/3)πr²h. If radius becomes 3r, new volume = (1/3)π(3r)²h = (1/3)π(9r²)h = 9 × (1/3)πr²h. So volume increases by 9 times.