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Unit 1: Locus — Online MCQ Test

MATHEMATICS - 1B · CLASS 11 INTERMEDIATE 1 YEAR · Telangana State Board
Practice Unit 1: Locus with a free chapter-wise online MCQ test. This chapter covers: This chapter introduces the definition of locus finding equations of loci under given geometrical conditions and geometric constraints on points.. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Unit 1: Locus — Important Questions & Answers

What is the locus of a point in a plane?
  • A. A curve or set of points satisfying a given condition
  • B. Only a straight line
  • C. Only a circle
  • D. Any random set of points
Answer: A. A curve or set of points satisfying a given condition
A locus is the path or set of all points that satisfy a specified geometric condition.
Which of the following is the locus of points equidistant from two fixed points?
  • A. The line joining the two points
  • B. The perpendicular bisector of the segment joining the two points
  • C. The angle bisector of the angle formed by the points
  • D. A circle with the two points as ends of a diameter
Answer: B. The perpendicular bisector of the segment joining the two points
The perpendicular bisector consists of all points equidistant from the two fixed points.
A point moves such that its distance from the x-axis is 3 units. What is the locus?
  • A. x = 3 or x = -3
  • B. y = 3 or y = -3
  • C. x^2 + y^2 = 9
  • D. y = x
Answer: B. y = 3 or y = -3
Distance from the x-axis is measured by the absolute value of the y-coordinate, so |y| = 3.
If a point P(x, y) is such that x + y = 5, what is the geometric interpretation of this locus?
  • A. A circle with center at origin
  • B. A straight line
  • C. A parabola
  • D. A point
Answer: B. A straight line
An equation of the form ax + by + c = 0 represents a straight line in the plane.
If a point P(x, y) satisfies the condition that its distance from the origin is equal to the square of its distance from the x-axis, then which equation represents the locus?
  • A. x^2 + y^2 = y^4
  • B. x^2 + y^2 = y^2
  • C. x^2 + y^2 = |y|
  • D. x^2 + y^2 = 2y^2
Answer: A. x^2 + y^2 = y^4
Distance from origin is √(x^2+y^2) and distance from x-axis is |y|. Squaring the given relation gives x^2 + y^2 = y^4.