Chapter 7: Moving Charges and Magnetism — Online MCQ Test
PHYSICS · CLASS 12 INTERMEDIATE 2 YEAR · Telangana State Board
Practice Chapter 7: Moving Charges and Magnetism with a free chapter-wise online MCQ test.
This chapter covers: Focusing on electromagnetism this chapter details Biot-Savart Law Ampere Circuital Law magnetic forces cyclotron motion force on current-carrying conductors and moving coil galvano....
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter 7: Moving Charges and Magnetism — Important Questions & Answers
What is the SI unit of magnetic field strength (magnetic induction)?
- A. Tesla
- B. Weber
- C. Ampere
- D. Henry
Answer: A. Tesla
The SI unit of magnetic induction (B) is the Tesla (T).
The SI unit of magnetic induction (B) is the Tesla (T).
The magnetic force on a charge q moving with velocity v in a magnetic field B is given by:
- A. F = q(v · B)
- B. F = q(v × B)
- C. F = q(B × v)
- D. F = q(v + B)
Answer: B. F = q(v × B)
The Lorentz magnetic force is defined by the cross product F = q(v × B).
The Lorentz magnetic force is defined by the cross product F = q(v × B).
The magnetic field at the center of a circular current-carrying loop of radius R is:
- A. μ₀I / 2R
- B. μ₀I / R
- C. μ₀I / 4R
- D. 2μ₀I / R
Answer: A. μ₀I / 2R
Applying the Biot-Savart law for a full circular loop yields B = μ₀I / 2R.
Applying the Biot-Savart law for a full circular loop yields B = μ₀I / 2R.
A charge particle enters a uniform magnetic field at an angle of 30 degrees. The path traced by the particle is:
- A. Straight line
- B. Circular
- C. Helical
- D. Parabolic
Answer: C. Helical
When velocity makes an angle with the B-field, the perpendicular component causes circular motion and parallel component keeps it moving, resulting in a helix.
When velocity makes an angle with the B-field, the perpendicular component causes circular motion and parallel component keeps it moving, resulting in a helix.
In a cyclotron, if the radius of the dees is doubled, the maximum kinetic energy of the accelerated particle will be:
- A. Double
- B. Four times
- C. Same
- D. Half
Answer: B. Four times
Kinetic Energy is proportional to R² (since v = qBR/m). Doubling R increases KE by 4.
Kinetic Energy is proportional to R² (since v = qBR/m). Doubling R increases KE by 4.