Chapter-12 Mensuration — Online MCQ Test
MATHS · Grade 10 · IGCSE cambridge
Practice Chapter-12 Mensuration with a free chapter-wise online MCQ test.
This chapter covers: Perimeter area and volume of 2D and 3D shapes including circles sectors cylinders cones and spheres..
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-12 Mensuration — Important Questions & Answers
What is the formula for the circumference of a circle with radius r?
- A. πr²
- B. 2πr
- C. πr
- D. πd²
Answer: B. 2πr
The circumference of a circle is 2πr, where r is the radius. This is the fundamental formula for the perimeter of a circle.
The circumference of a circle is 2πr, where r is the radius. This is the fundamental formula for the perimeter of a circle.
The area of a circle is 78.5 cm². What is its radius? (Use π ≈ 3.14)
- A. 5 cm
- B. 10 cm
- C. 2.5 cm
- D. 7.5 cm
Answer: A. 5 cm
Using A = πr², we have 78.5 = 3.14 × r². Solving gives r² = 25, so r = 5 cm.
Using A = πr², we have 78.5 = 3.14 × r². Solving gives r² = 25, so r = 5 cm.
A sector of a circle has a radius of 10 cm and a central angle of 60°. What is the area of the sector? (Use π ≈ 3.14)
- A. 52.33 cm²
- B. 314 cm²
- C. 157 cm²
- D. 26.17 cm²
Answer: A. 52.33 cm²
Area of sector = (θ/360°) × πr² = (60/360) × 3.14 × 100 = 52.33 cm².
Area of sector = (θ/360°) × πr² = (60/360) × 3.14 × 100 = 52.33 cm².
A sector of a circle has an arc length of 22 cm and radius 14 cm. What is its central angle? (Use π ≈ 22/7)
- A. 90°
- B. 75°
- C. 120°
- D. 60°
Answer: A. 90°
Arc length = (θ/360°) × 2πr. 22 = (θ/360) × 2 × (22/7) × 14. Solving gives θ = 90°.
Arc length = (θ/360°) × 2πr. 22 = (θ/360) × 2 × (22/7) × 14. Solving gives θ = 90°.
Two cylinders have the same volume. Cylinder A has radius 4 cm and height 10 cm. Cylinder B has radius 5 cm. What is the height of Cylinder B? (Use π ≈ 3.14)
- A. 6.4 cm
- B. 10 cm
- C. 5.12 cm
- D. 8 cm
Answer: A. 6.4 cm
V_A = π(4²)(10) = 160π. For V_B: 160π = π(5²)h_B, so h_B = 160/25 = 6.4 cm.
V_A = π(4²)(10) = 160π. For V_B: 160π = π(5²)h_B, so h_B = 160/25 = 6.4 cm.