Chapter Exam

Chapter-12 Mensuration — Online MCQ Test

Q: What is the formula for the circumference of a circle with radius r?

Answer: B. 2πr — The circumference of a circle is 2πr, where r is the radius. This is the fundamental formula for the perimeter of a circle.

Q: The area of a circle is 78.5 cm². What is its radius? (Use π ≈ 3.14)

Answer: A. 5 cm — Using A = πr², we have 78.5 = 3.14 × r². Solving gives r² = 25, so r = 5 cm.

Q: A sector of a circle has a radius of 10 cm and a central angle of 60°. What is the area of the sector? (Use π ≈ 3.14)

Answer: A. 52.33 cm² — Area of sector = (θ/360°) × πr² = (60/360) × 3.14 × 100 = 52.33 cm².

Q: A sector of a circle has an arc length of 22 cm and radius 14 cm. What is its central angle? (Use π ≈ 22/7)

Answer: A. 90° — Arc length = (θ/360°) × 2πr. 22 = (θ/360) × 2 × (22/7) × 14. Solving gives θ = 90°.

Q: Two cylinders have the same volume. Cylinder A has radius 4 cm and height 10 cm. Cylinder B has radius 5 cm. What is the height of Cylinder B? (Use π ≈ 3.14)

Answer: A. 6.4 cm — V_A = π(4²)(10) = 160π. For V_B: 160π = π(5²)h_B, so h_B = 160/25 = 6.4 cm.

MATHS · Grade 10 · IGCSE cambridge

Practice Chapter-12 Mensuration with a free chapter-wise online MCQ test for IGCSE cambridge Grade 10 MATHS. This chapter covers: Perimeter area and volume of 2D and 3D shapes including circles sectors cylinders cones and spheres.. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-12 Mensuration — Important Questions & Answers (FAQ)

Frequently asked questions from IGCSE cambridge Grade 10 MATHS — Chapter-12 Mensuration, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the formula for the circumference of a circle with radius r?

A. πr²
B. 2πr ✓
C. πr
D. πd²

Answer: B. 2πr
The circumference of a circle is 2πr, where r is the radius. This is the fundamental formula for the perimeter of a circle.

The area of a circle is 78.5 cm². What is its radius? (Use π ≈ 3.14)

A. 5 cm ✓
B. 10 cm
C. 2.5 cm
D. 7.5 cm

Answer: A. 5 cm
Using A = πr², we have 78.5 = 3.14 × r². Solving gives r² = 25, so r = 5 cm.

A sector of a circle has a radius of 10 cm and a central angle of 60°. What is the area of the sector? (Use π ≈ 3.14)

A. 52.33 cm² ✓
B. 314 cm²
C. 157 cm²
D. 26.17 cm²

Answer: A. 52.33 cm²
Area of sector = (θ/360°) × πr² = (60/360) × 3.14 × 100 = 52.33 cm².

A sector of a circle has an arc length of 22 cm and radius 14 cm. What is its central angle? (Use π ≈ 22/7)

A. 90° ✓
B. 75°
C. 120°
D. 60°

Answer: A. 90°
Arc length = (θ/360°) × 2πr. 22 = (θ/360) × 2 × (22/7) × 14. Solving gives θ = 90°.

Two cylinders have the same volume. Cylinder A has radius 4 cm and height 10 cm. Cylinder B has radius 5 cm. What is the height of Cylinder B? (Use π ≈ 3.14)