Chapter-9 Graphs of Functions — Online MCQ Test
MATHS · Grade 10 · IGCSE cambridge
Practice Chapter-9 Graphs of Functions with a free chapter-wise online MCQ test.
This chapter covers: Drawing and interpreting graphs of linear quadratic reciprocal and exponential functions..
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter-9 Graphs of Functions — Important Questions & Answers
Which of the following is the general form of a linear function?
- A. y = mx + c
- B. y = ax² + bx + c
- C. y = k/x
- D. y = a^x
Answer: A. y = mx + c
The linear function has the form y = mx + c, where m is the gradient and c is the y-intercept.
The linear function has the form y = mx + c, where m is the gradient and c is the y-intercept.
What is the vertex form of a quadratic function?
- A. y = mx + c
- B. y = a(x - h)² + k
- C. y = k/x
- D. y = ab^x
Answer: B. y = a(x - h)² + k
The vertex form y = a(x - h)² + k directly shows the vertex at point (h, k) and the direction of opening.
The vertex form y = a(x - h)² + k directly shows the vertex at point (h, k) and the direction of opening.
Which transformation moves the graph of y = x² to the right by 3 units?
- A. y = (x + 3)²
- B. y = (x - 3)²
- C. y = x² + 3
- D. y = x² - 3
Answer: B. y = (x - 3)²
Horizontal translations: subtracting a positive number from x shifts the graph right, so y = (x - 3)² shifts right by 3 units.
Horizontal translations: subtracting a positive number from x shifts the graph right, so y = (x - 3)² shifts right by 3 units.
A parabola has roots at x = 1 and x = 5. Which is the axis of symmetry?
- A. x = 1
- B. x = 2
- C. x = 3
- D. x = 5
Answer: C. x = 3
The axis of symmetry passes through the midpoint of the roots: x = (1 + 5)/2 = 6/2 = 3.
The axis of symmetry passes through the midpoint of the roots: x = (1 + 5)/2 = 6/2 = 3.
A function has a vertical asymptote at x = 2 and a horizontal asymptote at y = 1. Which function could it be?
- A. y = 1/(x - 2) + 1
- B. y = (x - 1)/(x - 2)
- C. y = 2/(x - 1) + 2
- D. y = (x + 1)/(x + 2)
Answer: A. y = 1/(x - 2) + 1
y = 1/(x - 2) + 1 has a vertical asymptote when x - 2 = 0 (x = 2) and a horizontal asymptote at y = 0 + 1 = 1.
y = 1/(x - 2) + 1 has a vertical asymptote when x - 2 = 0 (x = 2) and a horizontal asymptote at y = 0 + 1 = 1.