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Chapter-9 Graphs of Functions — Online MCQ Test

MATHS · Grade 10 · IGCSE cambridge

Practice Chapter-9 Graphs of Functions with a free chapter-wise online MCQ test for IGCSE cambridge Grade 10 MATHS. This chapter covers: Drawing and interpreting graphs of linear quadratic reciprocal and exponential functions.. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-9 Graphs of Functions — Important Questions & Answers (FAQ)

Frequently asked questions from IGCSE cambridge Grade 10 MATHS — Chapter-9 Graphs of Functions, with answers and explanations. These are sample questions; the exam has its own separate question set.

Which of the following is the general form of a linear function?
  • A. y = mx + c ✓
  • B. y = ax² + bx + c
  • C. y = k/x
  • D. y = a^x
Answer: A. y = mx + c
The linear function has the form y = mx + c, where m is the gradient and c is the y-intercept.
What is the vertex form of a quadratic function?
  • A. y = mx + c
  • B. y = a(x - h)² + k ✓
  • C. y = k/x
  • D. y = ab^x
Answer: B. y = a(x - h)² + k
The vertex form y = a(x - h)² + k directly shows the vertex at point (h, k) and the direction of opening.
Which transformation moves the graph of y = x² to the right by 3 units?
  • A. y = (x + 3)²
  • B. y = (x - 3)² ✓
  • C. y = x² + 3
  • D. y = x² - 3
Answer: B. y = (x - 3)²
Horizontal translations: subtracting a positive number from x shifts the graph right, so y = (x - 3)² shifts right by 3 units.
A parabola has roots at x = 1 and x = 5. Which is the axis of symmetry?
  • A. x = 1
  • B. x = 2
  • C. x = 3 ✓
  • D. x = 5
Answer: C. x = 3
The axis of symmetry passes through the midpoint of the roots: x = (1 + 5)/2 = 6/2 = 3.
A function has a vertical asymptote at x = 2 and a horizontal asymptote at y = 1. Which function could it be?
  • A. y = 1/(x - 2) + 1 ✓
  • B. y = (x - 1)/(x - 2)
  • C. y = 2/(x - 1) + 2
  • D. y = (x + 1)/(x + 2)
Answer: A. y = 1/(x - 2) + 1
y = 1/(x - 2) + 1 has a vertical asymptote when x - 2 = 0 (x = 2) and a horizontal asymptote at y = 0 + 1 = 1.

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