Chapter 3: Laws of Motion — Online MCQ Test
PHYSICS · CLASS 11th · Tamil Nadu State Board
Practice Chapter 3: Laws of Motion with a free chapter-wise online MCQ test.
This chapter covers: This chapter details Newton three laws of motion momentum conservation inertia friction and circular dynamics. Students analyze free body diagrams centripetal force banking of road....
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter 3: Laws of Motion — Important Questions & Answers
According to Newton's first law, a body remains at rest or in uniform motion unless acted upon by:
- A. Inertia
- B. An external unbalanced force
- C. Acceleration
- D. Gravitational pull
Answer: B. An external unbalanced force
Newton's first law states that an object continues in its state of rest or uniform motion unless an external unbalanced force acts on it.
Newton's first law states that an object continues in its state of rest or uniform motion unless an external unbalanced force acts on it.
Which of the following is a unit of momentum?
- A. kg m/s
- B. kg m/s^2
- C. N m
- D. Joule
Answer: A. kg m/s
Momentum is defined as the product of mass and velocity (p=mv), so its SI unit is kg m/s.
Momentum is defined as the product of mass and velocity (p=mv), so its SI unit is kg m/s.
If a force of 10 N is applied to a mass of 2 kg, the acceleration produced is:
- A. 5 m/s^2
- B. 20 m/s^2
- C. 0.2 m/s^2
- D. 2 m/s^2
Answer: A. 5 m/s^2
Using F=ma, a = F/m = 10/2 = 5 m/s^2.
Using F=ma, a = F/m = 10/2 = 5 m/s^2.
Two blocks of masses 2 kg and 3 kg are tied to a string and pulled with a force of 10 N. The acceleration of the system is:
- A. 1 m/s^2
- B. 2 m/s^2
- C. 5 m/s^2
- D. 10 m/s^2
Answer: B. 2 m/s^2
Total mass = 5 kg. a = F/m_total = 10/5 = 2 m/s^2.
Total mass = 5 kg. a = F/m_total = 10/5 = 2 m/s^2.
If the coefficient of static friction is 0.5, the angle of repose for an inclined plane is:
- A. 30 degrees
- B. 45 degrees
- C. 60 degrees
- D. arctan(0.5)
Answer: D. arctan(0.5)
The angle of repose (θ) is related to the coefficient of static friction (μ_s) by μ_s = tan(θ). Thus, θ = arctan(μ_s).
The angle of repose (θ) is related to the coefficient of static friction (μ_s) by μ_s = tan(θ). Thus, θ = arctan(μ_s).