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Chapter 3: Laws of Motion — Online MCQ Test

PHYSICS · CLASS 11th · Tamil Nadu State Board

Practice Chapter 3: Laws of Motion with a free chapter-wise online MCQ test for Tamil Nadu State Board CLASS 11th PHYSICS. This chapter covers: This chapter details Newton three laws of motion momentum conservation inertia friction and circular dynamics. Students analyze free body diagrams centripetal force banking of road.... AI-generated questions from basic to board-exam level, with instant results and explanations.

10
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20m
Time Limit
3
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  • Questions you've seen before won't repeat until the pool resets
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  • Results and explanations shown immediately after submission
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Chapter 3: Laws of Motion — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board CLASS 11th PHYSICS — Chapter 3: Laws of Motion, with answers and explanations. These are sample questions; the exam has its own separate question set.

According to Newton's first law, a body remains at rest or in uniform motion unless acted upon by:
  • A. Inertia
  • B. An external unbalanced force ✓
  • C. Acceleration
  • D. Gravitational pull
Answer: B. An external unbalanced force
Newton's first law states that an object continues in its state of rest or uniform motion unless an external unbalanced force acts on it.
Which of the following is a unit of momentum?
  • A. kg m/s ✓
  • B. kg m/s^2
  • C. N m
  • D. Joule
Answer: A. kg m/s
Momentum is defined as the product of mass and velocity (p=mv), so its SI unit is kg m/s.
If a force of 10 N is applied to a mass of 2 kg, the acceleration produced is:
  • A. 5 m/s^2 ✓
  • B. 20 m/s^2
  • C. 0.2 m/s^2
  • D. 2 m/s^2
Answer: A. 5 m/s^2
Using F=ma, a = F/m = 10/2 = 5 m/s^2.
Two blocks of masses 2 kg and 3 kg are tied to a string and pulled with a force of 10 N. The acceleration of the system is:
  • A. 1 m/s^2
  • B. 2 m/s^2 ✓
  • C. 5 m/s^2
  • D. 10 m/s^2
Answer: B. 2 m/s^2
Total mass = 5 kg. a = F/m_total = 10/5 = 2 m/s^2.
If the coefficient of static friction is 0.5, the angle of repose for an inclined plane is:
  • A. 30 degrees
  • B. 45 degrees
  • C. 60 degrees
  • D. arctan(0.5) ✓
Answer: D. arctan(0.5)
The angle of repose (θ) is related to the coefficient of static friction (μ_s) by μ_s = tan(θ). Thus, θ = arctan(μ_s).

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