Empowering Students with AI-Powered Assessments & Intelligent Learning
Chapter Exam

Chapter 4: Work Energy and Power — Online MCQ Test

PHYSICS · CLASS 11th · Tamil Nadu State Board

Practice Chapter 4: Work Energy and Power with a free chapter-wise online MCQ test for Tamil Nadu State Board CLASS 11th PHYSICS. This chapter covers: Focusing on mechanical energetics this chapter details work done by constant and variable forces work-energy theorem potential kinetic energy. Students examine conservative non-con.... AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
Login to Start This Exam →

New here? Register free — includes 3 free chapter exams.

Chapter 4: Work Energy and Power — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board CLASS 11th PHYSICS — Chapter 4: Work Energy and Power, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the SI unit of work?
  • A. Joule ✓
  • B. Watt
  • C. Newton
  • D. Pascal
Answer: A. Joule
Work is defined as force multiplied by displacement, and its SI unit is the Joule (J).
Which of the following is a scalar quantity?
  • A. Force
  • B. Work ✓
  • C. Displacement
  • D. Momentum
Answer: B. Work
Work is the dot product of force and displacement vectors, resulting in a scalar quantity.
If the velocity of a body is doubled, its kinetic energy becomes:
  • A. Double
  • B. Four times ✓
  • C. Half
  • D. Unchanged
Answer: B. Four times
Kinetic energy is proportional to the square of velocity (KE = 1/2 mv^2), so doubling v quadruples the KE.
A particle of mass m moves with constant speed v on a circular path of radius r. The work done in one complete revolution is:
  • A. mv^2/r * 2*pi*r
  • B. mv^2/r
  • C. Zero ✓
  • D. 2*pi*r*mv
Answer: C. Zero
Since the force is always perpendicular to displacement at every point, the total work done over a closed loop is zero.
A 10 kg mass moving at 5 m/s collides with a 5 kg mass at rest. If they stick together, what is the loss in kinetic energy?
  • A. 25 J
  • B. 41.67 J ✓
  • C. 83.33 J
  • D. 125 J
Answer: B. 41.67 J
Calculate initial KE, find final velocity using momentum conservation, calculate final KE, and find the difference.

Choose Your Plan & Start Practising

All plans cover every subject and chapter of your registered grade.

Free
₹0
3 exams · 1 year
Start Free →
Active
₹350
12 exams · 1 year
Get Active →
Pro
₹899
Unlimited exams · 1 year
Get Pro →
NEET
₹999
Unlimited exams · 1 year
Get NEET →

Compare all plans in detail →