Chapter 10: Probability Distributions — Online MCQ Test
STATISTICS · CLASS 11th · Tamil Nadu State Board
Practice Chapter 10: Probability Distributions with a free chapter-wise online MCQ test.
This chapter covers: The final chapter details theoretical probability distributions including Binomial Poisson and Normal distributions. Students study distribution properties parameters probability c....
AI-generated questions from basic to board-exam level, with instant results and explanations.
Chapter 10: Probability Distributions — Important Questions & Answers
In a binomial distribution, what does the parameter \u201cn\u201d represent?
- A. Probability of success in one trial
- B. Number of trials
- C. Mean of the distribution
- D. Standard deviation of the distribution
Answer: B. Number of trials
In a binomial distribution, n denotes the fixed number of independent trials. The probability of success is denoted by p.
In a binomial distribution, n denotes the fixed number of independent trials. The probability of success is denoted by p.
Which of the following is the formula for the probability mass function of a binomial distribution?
- A. P(X=x)=e^-\u03bb \u03bb^x / x!
- B. P(X=x)=1/(\u03c3\u221a2\u03c0)e^(-(x-\u03bc)^2/2\u03c3^2)
- C. P(X=x)=nCx p^x q^(n-x)
- D. P(X=x)=x/n
Answer: C. P(X=x)=nCx p^x q^(n-x)
The binomial probability formula is P(X=x)=nCx p^x q^(n-x), where q=1-p. It gives the probability of exactly x successes in n trials.
The binomial probability formula is P(X=x)=nCx p^x q^(n-x), where q=1-p. It gives the probability of exactly x successes in n trials.
A coin is tossed 5 times. What is the probability of getting exactly 2 heads?
- A. 5/16
- B. 10/32
- C. 1/2
- D. 2/5
Answer: B. 10/32
This is a binomial situation with n=5 and p=1/2. The probability is 5C2(1/2)^2(1/2)^3 = 10/32.
This is a binomial situation with n=5 and p=1/2. The probability is 5C2(1/2)^2(1/2)^3 = 10/32.
A binomial distribution has n = 10 and p = 0.3. What is its mean?
- A. 3
- B. 7
- C. 0.3
- D. 10.3
Answer: A. 3
The mean of a binomial distribution is np. Here, np = 10 \u00d7 0.3 = 3.
The mean of a binomial distribution is np. Here, np = 10 \u00d7 0.3 = 3.
A machine produces items with a defect probability of 0.1. In 8 items, what is the probability of at least one defective item?
- A. 1 - (0.9)^8
- B. (0.1)^8
- C. 8(0.1)(0.9)^7
- D. 1 - (0.1)^8
Answer: A. 1 - (0.9)^8
The probability of at least one defective item is 1 minus the probability of no defective items. Since each item is good with probability 0.9, the answer is 1-(0.9)^8.
The probability of at least one defective item is 1 minus the probability of no defective items. Since each item is good with probability 0.9, the answer is 1-(0.9)^8.