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Chapter 10: Probability Distributions — Online MCQ Test

STATISTICS · CLASS 11th · Tamil Nadu State Board

Practice Chapter 10: Probability Distributions with a free chapter-wise online MCQ test for Tamil Nadu State Board CLASS 11th STATISTICS. This chapter covers: The final chapter details theoretical probability distributions including Binomial Poisson and Normal distributions. Students study distribution properties parameters probability c.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 10: Probability Distributions — Important Questions & Answers (FAQ)

Frequently asked questions from Tamil Nadu State Board CLASS 11th STATISTICS — Chapter 10: Probability Distributions, with answers and explanations. These are sample questions; the exam has its own separate question set.

In a binomial distribution, what does the parameter \u201cn\u201d represent?
  • A. Probability of success in one trial
  • B. Number of trials ✓
  • C. Mean of the distribution
  • D. Standard deviation of the distribution
Answer: B. Number of trials
In a binomial distribution, n denotes the fixed number of independent trials. The probability of success is denoted by p.
Which of the following is the formula for the probability mass function of a binomial distribution?
  • A. P(X=x)=e^-\u03bb \u03bb^x / x!
  • B. P(X=x)=1/(\u03c3\u221a2\u03c0)e^(-(x-\u03bc)^2/2\u03c3^2)
  • C. P(X=x)=nCx p^x q^(n-x) ✓
  • D. P(X=x)=x/n
Answer: C. P(X=x)=nCx p^x q^(n-x)
The binomial probability formula is P(X=x)=nCx p^x q^(n-x), where q=1-p. It gives the probability of exactly x successes in n trials.
A coin is tossed 5 times. What is the probability of getting exactly 2 heads?
  • A. 5/16
  • B. 10/32 ✓
  • C. 1/2
  • D. 2/5
Answer: B. 10/32
This is a binomial situation with n=5 and p=1/2. The probability is 5C2(1/2)^2(1/2)^3 = 10/32.
A binomial distribution has n = 10 and p = 0.3. What is its mean?
  • A. 3 ✓
  • B. 7
  • C. 0.3
  • D. 10.3
Answer: A. 3
The mean of a binomial distribution is np. Here, np = 10 \u00d7 0.3 = 3.
A machine produces items with a defect probability of 0.1. In 8 items, what is the probability of at least one defective item?
  • A. 1 - (0.9)^8 ✓
  • B. (0.1)^8
  • C. 8(0.1)(0.9)^7
  • D. 1 - (0.1)^8
Answer: A. 1 - (0.9)^8
The probability of at least one defective item is 1 minus the probability of no defective items. Since each item is good with probability 0.9, the answer is 1-(0.9)^8.

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