Chapter 2: Sets — Online MCQ Test
MATHS · CLASS 10th · Telangana State Board
Practice Chapter 2: Sets with a free chapter-wise online MCQ test.
This chapter covers: This chapter introduces the fundamental language of set theory.
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Chapter 2: Sets — Important Questions & Answers
Which of the following is the correct definition of a set?
- A. A collection of well-defined distinct objects
- B. A group of similar numbers only
- C. Any arrangement of elements in order
- D. A list of random items
Answer: A. A collection of well-defined distinct objects
A set is defined as a collection of well-defined, distinct objects called elements. The elements must be clearly identifiable and unique.
A set is defined as a collection of well-defined, distinct objects called elements. The elements must be clearly identifiable and unique.
Which notation is used to represent that an element belongs to a set?
- A. ⊂
- B. ∈
- C. ⊆
- D. ≠
Answer: B. ∈
The symbol ∈ (epsilon) is used to denote that an element belongs to a set, while ⊂ denotes subset relationship.
The symbol ∈ (epsilon) is used to denote that an element belongs to a set, while ⊂ denotes subset relationship.
If A = {1, 2, 3} and B = {2, 3, 4}, then A ∪ B equals?
- A. {2, 3}
- B. {1, 2, 3, 4}
- C. {1, 4}
- D. { }
Answer: B. {1, 2, 3, 4}
The union of two sets contains all elements that belong to either set A or set B or both. Therefore, A ∪ B = {1, 2, 3, 4}.
The union of two sets contains all elements that belong to either set A or set B or both. Therefore, A ∪ B = {1, 2, 3, 4}.
If A = {1, 2} and B = {1, 2, 3, 4}, then which statement is true?
- A. A ⊃ B
- B. A ⊂ B
- C. A = B
- D. A and B are disjoint sets
Answer: B. A ⊂ B
Since every element of A is also in B, but B has additional elements (3 and 4), A is a proper subset of B, denoted as A ⊂ B.
Since every element of A is also in B, but B has additional elements (3 and 4), A is a proper subset of B, denoted as A ⊂ B.
In a class of 100 students, 60 like Mathematics and 75 like Science. If every student likes at least one subject, how many students like both subjects?
- A. 25
- B. 35
- C. 40
- D. 50
Answer: B. 35
Using n(M ∪ S) = n(M) + n(S) - n(M ∩ S), we get 100 = 60 + 75 - n(M ∩ S), so n(M ∩ S) = 135 - 100 = 35.
Using n(M ∪ S) = n(M) + n(S) - n(M ∩ S), we get 100 = 60 + 75 - n(M ∩ S), so n(M ∩ S) = 135 - 100 = 35.