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Chapter 2: Sets — Online MCQ Test

MATHS · CLASS 10th · Telangana State Board

Practice Chapter 2: Sets with a free chapter-wise online MCQ test for Telangana State Board CLASS 10th MATHS. This chapter covers: This chapter introduces the fundamental language of set theory. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 2: Sets — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 10th MATHS — Chapter 2: Sets, with answers and explanations. These are sample questions; the exam has its own separate question set.

Which of the following is the correct definition of a set?
  • A. A collection of well-defined distinct objects ✓
  • B. A group of similar numbers only
  • C. Any arrangement of elements in order
  • D. A list of random items
Answer: A. A collection of well-defined distinct objects
A set is defined as a collection of well-defined, distinct objects called elements. The elements must be clearly identifiable and unique.
Which notation is used to represent that an element belongs to a set?
  • A. ⊂
  • B. ∈ ✓
  • C. ⊆
  • D. ≠
Answer: B. ∈
The symbol ∈ (epsilon) is used to denote that an element belongs to a set, while ⊂ denotes subset relationship.
If A = {1, 2, 3} and B = {2, 3, 4}, then A ∪ B equals?
  • A. {2, 3}
  • B. {1, 2, 3, 4} ✓
  • C. {1, 4}
  • D. { }
Answer: B. {1, 2, 3, 4}
The union of two sets contains all elements that belong to either set A or set B or both. Therefore, A ∪ B = {1, 2, 3, 4}.
If A = {1, 2} and B = {1, 2, 3, 4}, then which statement is true?
  • A. A ⊃ B
  • B. A ⊂ B ✓
  • C. A = B
  • D. A and B are disjoint sets
Answer: B. A ⊂ B
Since every element of A is also in B, but B has additional elements (3 and 4), A is a proper subset of B, denoted as A ⊂ B.
In a class of 100 students, 60 like Mathematics and 75 like Science. If every student likes at least one subject, how many students like both subjects?
  • A. 25
  • B. 35 ✓
  • C. 40
  • D. 50
Answer: B. 35
Using n(M ∪ S) = n(M) + n(S) - n(M ∩ S), we get 100 = 60 + 75 - n(M ∩ S), so n(M ∩ S) = 135 - 100 = 35.

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