Unit 9: Gravitation — Online MCQ Test
PHYSICS · CLASS 11 INTERMEDIATE 1 YEAR · Telangana State Board
Practice Unit 9: Gravitation with a free chapter-wise online MCQ test.
This chapter covers: Focusing on celestial mechanics this chapter details Universal Law of Gravitation acceleration due to gravity variation with altitude and depth Kepler laws escape speed orbital vel....
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Unit 9: Gravitation — Important Questions & Answers
What is the SI unit of the universal gravitational constant G?
- A. N m^2 kg^-2
- B. N kg^-2 m^2
- C. kg m^2 s^-2
- D. m s^-2
Answer: A. N m^2 kg^-2
The universal gravitational constant appears in Newton's law of gravitation as F = G m1 m2 / r^2, so its SI unit is N m^2 kg^-2.
The universal gravitational constant appears in Newton's law of gravitation as F = G m1 m2 / r^2, so its SI unit is N m^2 kg^-2.
The acceleration due to gravity on the surface of the Earth is approximately:
- A. 9.8 m/s^2
- B. 98 m/s^2
- C. 0.98 m/s^2
- D. 1.8 m/s^2
Answer: A. 9.8 m/s^2
The standard value of acceleration due to gravity near Earth's surface is about 9.8 m/s^2.
The standard value of acceleration due to gravity near Earth's surface is about 9.8 m/s^2.
If the distance between two masses is doubled, the gravitational force between them becomes:
- A. twice
- B. half
- C. one-fourth
- D. four times
Answer: C. one-fourth
According to Newton's law of gravitation, force varies inversely as the square of distance. So doubling the distance reduces the force to one-fourth.
According to Newton's law of gravitation, force varies inversely as the square of distance. So doubling the distance reduces the force to one-fourth.
A body is taken from the Earth's surface to a depth equal to half the Earth's radius. Assuming uniform density, the acceleration due to gravity becomes:
- A. g
- B. g/2
- C. g/4
- D. zero
Answer: B. g/2
Inside a uniform Earth, acceleration due to gravity decreases linearly with depth: g' = g(1 - d/R). For d = R/2, g' = g/2.
Inside a uniform Earth, acceleration due to gravity decreases linearly with depth: g' = g(1 - d/R). For d = R/2, g' = g/2.
A geostationary satellite must have which of the following conditions?
- A. Orbit perpendicular to the equator and time period of 12 hours
- B. Orbit in the equatorial plane and time period equal to Earth's rotation period
- C. Any orbit with period less than 24 hours
- D. Polar orbit with speed equal to escape speed
Answer: B. Orbit in the equatorial plane and time period equal to Earth's rotation period
For a satellite to appear fixed over one point on Earth, it must orbit in the equatorial plane with a period equal to Earth's rotation period.
For a satellite to appear fixed over one point on Earth, it must orbit in the equatorial plane with a period equal to Earth's rotation period.