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Unit 9: Gravitation — Online MCQ Test

PHYSICS · CLASS 11 INTERMEDIATE 1 YEAR · Telangana State Board

Practice Unit 9: Gravitation with a free chapter-wise online MCQ test for Telangana State Board CLASS 11 INTERMEDIATE 1 YEAR PHYSICS. This chapter covers: Focusing on celestial mechanics this chapter details Universal Law of Gravitation acceleration due to gravity variation with altitude and depth Kepler laws escape speed orbital vel.... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Unit 9: Gravitation — Important Questions & Answers (FAQ)

Frequently asked questions from Telangana State Board CLASS 11 INTERMEDIATE 1 YEAR PHYSICS — Unit 9: Gravitation, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the SI unit of the universal gravitational constant G?
  • A. N m^2 kg^-2 ✓
  • B. N kg^-2 m^2
  • C. kg m^2 s^-2
  • D. m s^-2
Answer: A. N m^2 kg^-2
The universal gravitational constant appears in Newton's law of gravitation as F = G m1 m2 / r^2, so its SI unit is N m^2 kg^-2.
The acceleration due to gravity on the surface of the Earth is approximately:
  • A. 9.8 m/s^2 ✓
  • B. 98 m/s^2
  • C. 0.98 m/s^2
  • D. 1.8 m/s^2
Answer: A. 9.8 m/s^2
The standard value of acceleration due to gravity near Earth's surface is about 9.8 m/s^2.
If the distance between two masses is doubled, the gravitational force between them becomes:
  • A. twice
  • B. half
  • C. one-fourth ✓
  • D. four times
Answer: C. one-fourth
According to Newton's law of gravitation, force varies inversely as the square of distance. So doubling the distance reduces the force to one-fourth.
A body is taken from the Earth's surface to a depth equal to half the Earth's radius. Assuming uniform density, the acceleration due to gravity becomes:
  • A. g
  • B. g/2 ✓
  • C. g/4
  • D. zero
Answer: B. g/2
Inside a uniform Earth, acceleration due to gravity decreases linearly with depth: g' = g(1 - d/R). For d = R/2, g' = g/2.
A geostationary satellite must have which of the following conditions?
  • A. Orbit perpendicular to the equator and time period of 12 hours
  • B. Orbit in the equatorial plane and time period equal to Earth's rotation period ✓
  • C. Any orbit with period less than 24 hours
  • D. Polar orbit with speed equal to escape speed
Answer: B. Orbit in the equatorial plane and time period equal to Earth's rotation period
For a satellite to appear fixed over one point on Earth, it must orbit in the equatorial plane with a period equal to Earth's rotation period.

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