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Chapter 8: Introduction to Trigonometry — Online MCQ Test

MATHS · CLASS 10 · Andhra State Board

Practice Chapter 8: Introduction to Trigonometry with a free chapter-wise online MCQ test for Andhra State Board CLASS 10 MATHS. This chapter covers: Trigonometric ratios Sine Cosine Tangent Cosecant Secant Cotangent Standard angles Trigonometric identities Complementary angles. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
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  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter 8: Introduction to Trigonometry — Important Questions & Answers (FAQ)

Frequently asked questions from Andhra State Board CLASS 10 MATHS — Chapter 8: Introduction to Trigonometry, with answers and explanations. These are sample questions; the exam has its own separate question set.

In a right-angled triangle, sin A is equal to:
  • A. Opposite side/Hypotenuse ✓
  • B. Adjacent side/Hypotenuse
  • C. Opposite side/Adjacent side
  • D. Hypotenuse/Opposite side
Answer: A. Opposite side/Hypotenuse
By definition, sin A = perpendicular or opposite side divided by hypotenuse.
The value of tan A in terms of sin A and cos A is:
  • A. cos A/sin A
  • B. sin A/cos A ✓
  • C. 1/(sin A cos A)
  • D. sin A + cos A
Answer: B. sin A/cos A
The identity tan A = sin A/cos A is a basic trigonometric relation.
In a right triangle, for an acute angle A, the side opposite A is 3 cm and the hypotenuse is 5 cm. What is sin A?
  • A. 3/5 ✓
  • B. 4/5
  • C. 3/4
  • D. 5/3
Answer: A. 3/5
sin A = opposite side/hypotenuse = 3/5.
If sin A + cos A = √2 for an acute angle A, then tan A + cot A is:
  • A. 1
  • B. 2 ✓
  • C. √2
  • D. 4
Answer: B. 2
Squaring sin A + cos A = √2 gives 1 + 2 sin A cos A = 2, so sin A cos A = 1/2. Thus tan A + cot A = 1/(sin A cos A) = 2.
If tan θ + sec θ = p, then (1 - sin θ)/(1 + sin θ) is equal to:
  • A. p²
  • B. 1/p² ✓
  • C. p
  • D. 1/p
Answer: B. 1/p²
Since tan θ + sec θ = (1 + sin θ)/cos θ = p and sec θ - tan θ = 1/p, the ratio (1 - sin θ)/(1 + sin θ) = 1/p².

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