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Chapter-1 - Real Numbers — Online MCQ Test

MATHS · Grade 10 · CBSE(NCERT)

Practice Chapter-1 - Real Numbers with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 10 MATHS. This chapter covers: First Chapter. AI-generated questions from basic to board-exam level, with instant results and explanations.

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20m
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  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
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  • Results and explanations shown immediately after submission
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Chapter-1 - Real Numbers — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 10 MATHS — Chapter-1 - Real Numbers, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the name of the theorem that states every composite number can be uniquely expressed as a product of primes?
  • A. Euclid's Division Lemma
  • B. Fundamental Theorem of Arithmetic ✓
  • C. Fundamental Theorem of Algebra
  • D. Prime Factorization Theorem
Answer: B. Fundamental Theorem of Arithmetic
The Fundamental Theorem of Arithmetic states that every composite number can be uniquely expressed as a product of primes, apart from the order of factors.
Numbers having non-terminating, non-repeating decimal expansion are known as:
  • A. Rational numbers
  • B. Natural numbers
  • C. Irrational numbers ✓
  • D. Integers
Answer: C. Irrational numbers
Irrational numbers have non-terminating and non-repeating decimal expansions, which distinguishes them from rational numbers.
Let x = 13/(2² × 5⁴). How many decimal places will x have when expanded as a terminating decimal?
  • A. 2
  • B. 3
  • C. 4 ✓
  • D. 5
Answer: C. 4
The number of decimal places in a terminating decimal equals the highest power among 2 and 5 in the denominator. Here max(2, 4) = 4.
In the proof of irrationality of √2, a contradiction is reached because:
  • A. 2 cannot be expressed as a fraction
  • B. Both a and b turn out to be divisible by 2, contradicting the assumption that they are coprime ✓
  • C. a² cannot equal 2b² for any integers
  • D. b must equal zero
Answer: B. Both a and b turn out to be divisible by 2, contradicting the assumption that they are coprime
The proof shows that both a and b must be divisible by 2, which contradicts the initial assumption that a/b is in lowest terms (coprime).
If p and q are distinct primes, what is HCF(p², q²)?
  • A. pq
  • B. p²q²
  • C. 1 ✓
  • D. p²
Answer: C. 1
Since p and q are distinct primes, p² = p×p and q² = q×q share no common prime factors. Therefore HCF(p², q²) = 1.

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