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Chapter 10: Circles — Online MCQ Test

MATHS · Grade 10 · CBSE(NCERT)

Practice Chapter 10: Circles with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 10 MATHS. This chapter covers: Tangent Secant Radius Point of contact Number of tangents Equal tangents Tangent properties Circle theorems. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
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  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter 10: Circles — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 10 MATHS — Chapter 10: Circles, with answers and explanations. These are sample questions; the exam has its own separate question set.

A line that touches a circle at exactly one point is called a:
  • A. Secant
  • B. Tangent ✓
  • C. Chord
  • D. Diameter
Answer: B. Tangent
A tangent to a circle touches it at exactly one point, called the point of contact.
The radius drawn to the point of contact of a tangent is:
  • A. Parallel to the tangent
  • B. Perpendicular to the tangent ✓
  • C. Equal to the tangent
  • D. A secant of the circle
Answer: B. Perpendicular to the tangent
According to the tangent-radius theorem, the radius through the point of contact is perpendicular to the tangent.
From an external point P, a tangent PA is drawn to a circle with centre O. If OP = 13 cm and OA = 5 cm, then PA is:
  • A. 8 cm
  • B. 10 cm
  • C. 12 cm ✓
  • D. 18 cm
Answer: C. 12 cm
Since OA is perpendicular to PA, triangle OAP is right-angled. PA = √(13² - 5²) = √144 = 12 cm.
Tangents PA and PB are drawn from P to a circle with centre O. If ∠APB = 80°, then ∠OAB is:
  • A. 40° ✓
  • B. 50°
  • C. 80°
  • D. 100°
Answer: A. 40°
Here ∠AOB = 180° - 80° = 100°. In isosceles triangle AOB, ∠OAB = (180° - 100°)/2 = 40°.
From point P, tangents PA and PB are drawn to a circle with centre O. If ∠APB = 2x + 20° and ∠AOB = 3x + 10°, then x is:
  • A. 20°
  • B. 30° ✓
  • C. 40°
  • D. 50°
Answer: B. 30°
The angles ∠APB and ∠AOB are supplementary, so (2x + 20) + (3x + 10) = 180. This gives x = 30°.

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