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Chapter 2 - Relations and Functions — Online MCQ Test

MATHS · Grade 11 · CBSE(NCERT)

Practice Chapter 2 - Relations and Functions with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 11 MATHS. This chapter covers: Relations and Functions. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 2 - Relations and Functions — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 11 MATHS — Chapter 2 - Relations and Functions, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is a relation in mathematics?
  • A. A subset of the Cartesian product of two sets ✓
  • B. A function that maps every element to itself
  • C. A set of ordered pairs with no specific rule
  • D. An equivalence between two algebraic expressions
Answer: A. A subset of the Cartesian product of two sets
A relation is formally defined as a subset of the Cartesian product A × B, where A and B are two sets.
If A = {1, 2, 3} and B = {a, b}, how many elements are in A × B?
  • A. 3
  • B. 5
  • C. 6 ✓
  • D. 2
Answer: C. 6
The Cartesian product A × B has |A| × |B| = 3 × 2 = 6 elements.
If f(x) = x² and g(x) = x + 1, what is (f ∘ g)(2)?
  • A. 5
  • B. 9 ✓
  • C. 8
  • D. 7
Answer: B. 9
(f ∘ g)(2) = f(g(2)) = f(3) = 3² = 9. First apply g, then apply f to the result.
A relation that is reflexive, antisymmetric, and transitive is called a _____.
  • A. Equivalence relation
  • B. Partial order relation ✓
  • C. Congruence relation
  • D. Total relation
Answer: B. Partial order relation
A partial order (or partial ordering) is a relation that is reflexive, antisymmetric, and transitive.
Consider the function f: Z → Z defined by f(n) = n/2 if n is even, and f(n) = (n+1)/2 if n is odd. Is f surjective?
  • A. Yes, f is surjective because every integer has a pre-image ✓
  • B. No, because f is not defined for all integers
  • C. Yes, f is surjective because it covers all even integers
  • D. No, because negative integers cannot be in the range
Answer: A. Yes, f is surjective because every integer has a pre-image
For any integer m in Z, we can find an integer n such that f(n) = m. For example, if m ≥ 0, take n = 2m (even), then f(2m) = m. Thus f is onto (surjective).

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