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Chapter-2 Motion in a Straight Line — Online MCQ Test

PHYSICS · Grade 11 · CBSE(NCERT)

Practice Chapter-2 Motion in a Straight Line with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 11 PHYSICS. This chapter covers: Frame of reference - Position-time graph - Velocity-time graph - Instantaneous velocity - Uniform acceleration - Kinematic equations - Relative velocity. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
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  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-2 Motion in a Straight Line — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 11 PHYSICS — Chapter-2 Motion in a Straight Line, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is a frame of reference in physics?
  • A. A coordinate system used to measure position, velocity, and acceleration of an object ✓
  • B. The path traced by a moving object
  • C. The speed of an object at any given instant
  • D. The total distance covered by an object
Answer: A. A coordinate system used to measure position, velocity, and acceleration of an object
A frame of reference is a coordinate system or set of axes from which positions and motions are measured and described.
In a position-time graph, what does the slope represent?
  • A. Acceleration of the object
  • B. Velocity of the object ✓
  • C. Distance traveled by the object
  • D. Force acting on the object
Answer: B. Velocity of the object
The slope of a position-time graph is the rate of change of position with respect to time, which is velocity.
A car travels 100 m in the first 5 seconds and 150 m in the next 5 seconds. What is the average velocity for the entire motion?
  • A. 20 m/s
  • B. 30 m/s
  • C. 25 m/s ✓
  • D. 15 m/s
Answer: C. 25 m/s
Average velocity = Total displacement / Total time = (100 + 150) m / (5 + 5) s = 250 m / 10 s = 25 m/s.
A stone is thrown downward from a cliff with an initial velocity of 5 m/s. If it hits the ground in 2 seconds, what is the displacement? (Take g = 10 m/s²)
  • A. 10 m
  • B. 20 m
  • C. 30 m ✓
  • D. 40 m
Answer: C. 30 m
Using s = ut + ½gt² with u = 5 m/s, g = 10 m/s², and t = 2 s: s = 5(2) + ½(10)(2)² = 10 + 20 = 30 m.
A car moving at 72 km/h needs to stop in 5 seconds. What is the minimum acceleration (deceleration) required, and how far will it travel before stopping?
  • A. -4 m/s² and 50 m ✓
  • B. -4 m/s² and 45 m
  • C. -5 m/s² and 40 m
  • D. -6 m/s² and 60 m
Answer: A. -4 m/s² and 50 m
Converting 72 km/h = 20 m/s. Using v = u + at: 0 = 20 + a(5), so a = -4 m/s². Distance: s = ut + ½at² = 20(5) + ½(-4)(25) = 100 - 50 = 50 m.

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