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Chapter 10: Vector Algebra — Online MCQ Test

MATHS · Grade 12 · CBSE(NCERT)

Practice Chapter 10: Vector Algebra with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 12 MATHS. This chapter covers: Vector Definition: A vector is a mathematical quantity that possesses both a magnitude (length) and a definite direction in space.Direction Cosines: The direction cosines (l, m, n).... AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 10: Vector Algebra — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 12 MATHS — Chapter 10: Vector Algebra, with answers and explanations. These are sample questions; the exam has its own separate question set.

A vector is a mathematical quantity that possesses which of the following characteristics?
  • A. Only magnitude
  • B. Only direction
  • C. Both magnitude and direction ✓
  • D. Neither magnitude nor direction
Answer: C. Both magnitude and direction
By definition, a vector has both magnitude (length) and a definite direction in space.
Find the magnitude of the vector vec{a} = 3î + 4ĵ.
  • A. 5 ✓
  • B. 7
  • C. 12
  • D. 25
Answer: A. 5
Magnitude |vec{a}| = √(3² + 4²) = √(9 + 16) = √25 = 5.
Calculate vec{a} · vec{b} for vec{a} = 2î + 3ĵ and vec{b} = 4î + 5ĵ.
  • A. 8
  • B. 15
  • C. 23 ✓
  • D. 35
Answer: C. 23
vec{a} · vec{b} = (2)(4) + (3)(5) = 8 + 15 = 23.
Three points A, B, and C are collinear if which condition is satisfied?
  • A. vec{AB} · vec{BC} = 0
  • B. vec{AB} × vec{BC} = 0 ✓
  • C. |vec{AB}| = |vec{BC}|
  • D. vec{AB} + vec{BC} = vec{AC}
Answer: B. vec{AB} × vec{BC} = 0
Three points are collinear if the vectors formed by them are parallel, which means their cross product is zero.
The vectors vec{a} = xî + ĵ + k̂, vec{b} = î + yĵ + k̂, and vec{c} = î + ĵ + zk̂ are mutually perpendicular. Which statement is correct?
  • A. x = y = z = -1
  • B. x + y + z = -2 ✓
  • C. xyz = 1
  • D. x = 1, y = 1, z = 1
Answer: B. x + y + z = -2
From vec{a}·vec{b}=0, vec{b}·vec{c}=0, vec{c}·vec{a}=0, we get x+y = -1, y+z = -1, z+x = -1. Solving: x+y+z = -2.

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