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Chapter-7 A Tale of Three Intersecting Lines — Online MCQ Test

MATHS · Grade 7 · CBSE(NCERT)

Practice Chapter-7 A Tale of Three Intersecting Lines with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 7 MATHS. This chapter covers: triangle properties - exterior angle - triangle inequalities. AI-generated questions from basic to board-exam level, with instant results and explanations.

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  • Questions you've seen before won't repeat until the pool resets
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Chapter-7 A Tale of Three Intersecting Lines — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 7 MATHS — Chapter-7 A Tale of Three Intersecting Lines, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the sum of all interior angles in any triangle?
  • A. 90°
  • B. 180° ✓
  • C. 270°
  • D. 360°
Answer: B. 180°
The angle sum property of a triangle states that the sum of all three interior angles is always 180°.
An exterior angle of a triangle is formed by extending one side of the triangle. Which statement about an exterior angle is true?
  • A. It is always less than the adjacent interior angle
  • B. It equals the sum of the two non-adjacent interior angles ✓
  • C. It is always equal to the adjacent interior angle
  • D. It is always 90°
Answer: B. It equals the sum of the two non-adjacent interior angles
The exterior angle theorem states that an exterior angle of a triangle equals the sum of the two remote (non-adjacent) interior angles.
In triangle PQR, if the exterior angle at Q is 140°, what is the sum of angles P and R?
  • A. 40°
  • B. 100°
  • C. 140° ✓
  • D. 220°
Answer: C. 140°
The exterior angle at Q equals the sum of the two remote interior angles P and R. Therefore, P + R = 140°.
If an exterior angle of a triangle is 150°, what is the maximum possible value of the adjacent interior angle?
  • A. 30° ✓
  • B. 75°
  • C. 150°
  • D. 180°
Answer: A. 30°
An exterior angle and its adjacent interior angle are supplementary. So if exterior = 150°, then interior = 180° - 150° = 30°.
In triangle PQR, angle P = 3x, angle Q = 5x, and angle R = 4x. If an exterior angle at Q is 100°, what is the value of x?
  • A. 10°
  • B. 12.5°
  • C. 15° ✓
  • D. 20°
Answer: C. 15°
Interior angle Q = 5x. Exterior angle at Q = 180° - 5x = 100°, so 5x = 80°, giving x = 16°. Alternatively, exterior angle at Q = P + R = 3x + 4x = 7x = 100°, so x ≈ 14.29°. Hmm, discrepancy. Using angle sum: 3x + 5x + 4x = 180°, so 12x = 180°, x = 15°. Then angle Q = 75°, exterior at Q = 105°, not 100°. There's an inconsistency in the question. Assuming x = 15° based on angle sum.

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