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Chapter-5 Number Play — Online MCQ Test

MATHS · Grade 8 · CBSE(NCERT)

Practice Chapter-5 Number Play with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 8 MATHS. This chapter covers: generalized form - divisibility tests - letters for digits - cryptarithms - number puzzles. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-5 Number Play — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 8 MATHS — Chapter-5 Number Play, with answers and explanations. These are sample questions; the exam has its own separate question set.

A number is divisible by 2 if its last digit is ______.
  • A. odd
  • B. even ✓
  • C. prime
  • D. greater than 5
Answer: B. even
A number is divisible by 2 if and only if its last digit is even (0, 2, 4, 6, 8).
What is the divisibility test for 5?
  • A. The sum of digits must be divisible by 5
  • B. The last digit must be 0 or 5 ✓
  • C. The number must be even
  • D. All digits must be divisible by 5
Answer: B. The last digit must be 0 or 5
A number is divisible by 5 if its last digit is either 0 or 5.
If a three-digit number is written as 'abc' in generalized form, its value is ______.
  • A. a + b + c
  • B. 100a + 10b + c ✓
  • C. abc
  • D. 100(a + b + c)
Answer: B. 100a + 10b + c
A three-digit number 'abc' has value 100a + 10b + c, where a is in hundreds place, b in tens place, and c in units place.
If a number 'abc' is divisible by 11, then which condition must be true?
  • A. a + b + c is divisible by 11
  • B. (a - b + c) is divisible by 11 ✓
  • C. a + b + c is even
  • D. abc must be a three-digit prime
Answer: B. (a - b + c) is divisible by 11
The divisibility test for 11 for a three-digit number 'abc' is: (a - b + c) must be divisible by 11, or more generally, the alternating sum of digits must be divisible by 11.
If PQ + QR + RP = PQR, where P, Q, R are distinct digits, then what is the value of P?
  • A. 1 ✓
  • B. 2
  • C. 3
  • D. 4
Answer: A. 1
PQ + QR + RP = (10P+Q) + (10Q+R) + (10R+P) = 11P + 11Q + 11R = 11(P+Q+R). For this to equal PQR = 100P + 10Q + R, we need 11(P+Q+R) = 100P + 10Q + R. Simplifying: 11P + 11Q + 11R = 100P + 10Q + R gives Q + 10R = 89P, which works when P=1.

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