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Chapter-6 Number Play — Online MCQ Test

MATHS (KANITHA PRAKASH) · CLASS 7th · Karnataka State Board

Practice Chapter-6 Number Play with a free chapter-wise online MCQ test for Karnataka State Board CLASS 7th MATHS (KANITHA PRAKASH). This chapter covers: parity - Fibonacci sequence - cryptarithms - number patterns. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-6 Number Play — Important Questions & Answers (FAQ)

Frequently asked questions from Karnataka State Board CLASS 7th MATHS (KANITHA PRAKASH) — Chapter-6 Number Play, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the definition of an even number?
  • A. A number divisible by 2 ✓
  • B. A number divisible by 3
  • C. A number greater than 10
  • D. A number with two digits
Answer: A. A number divisible by 2
An even number is any integer that can be divided by 2 without a remainder.
Which of the following is an odd number?
  • A. 24
  • B. 35 ✓
  • C. 42
  • D. 50
Answer: B. 35
35 is odd because it leaves a remainder of 1 when divided by 2, unlike 24, 42, and 50 which are all even.
What is the sum of an even number and an odd number?
  • A. Always even
  • B. Always odd ✓
  • C. Sometimes even, sometimes odd
  • D. Always zero
Answer: B. Always odd
The sum of an even number and an odd number is always odd (e.g., 2 + 3 = 5; 4 + 5 = 9).
In the cryptarithm puzzle, if AB + BA = CDC, where A, B, C, D are different digits, which statement must be true?
  • A. A + B must be less than 10
  • B. A + B must be greater than 10
  • C. C must be 1 ✓
  • D. D must be 0
Answer: C. C must be 1
When two 2-digit numbers add to a 3-digit number, the result must be between 100-198, so C must be 1.
In a complex cryptarithm where HE + LOVES = MATH, what is the maximum possible value for the digit represented by M?
  • A. 9
  • B. 8
  • C. 2
  • D. 1 ✓
Answer: D. 1
Since HE (max 98) + LOVES (max 98765) cannot exceed 99863, M can only be 1 because the sum of a 2-digit and 5-digit number starting with different letters in a cryptarithm context creates a result where M=1.

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