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Chapter 11: Electricity — Online MCQ Test

SCIENCE · CLASS 10 · Andhra State Board

Practice Chapter 11: Electricity with a free chapter-wise online MCQ test for Andhra State Board CLASS 10 SCIENCE. This chapter covers: Electric charge Electric current Potential difference Voltage Resistance Ohms law Resistivity Series circuit Parallel circuit Electric power Heating effect. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter 11: Electricity — Important Questions & Answers (FAQ)

Frequently asked questions from Andhra State Board CLASS 10 SCIENCE — Chapter 11: Electricity, with answers and explanations. These are sample questions; the exam has its own separate question set.

The SI unit of electric current is:
  • A. ampere ✓
  • B. volt
  • C. ohm
  • D. coulomb
Answer: A. ampere
Electric current is the rate of flow of charge. Its SI unit is ampere (A).
Electric current in a conductor is defined as the:
  • A. work done per unit charge
  • B. charge flowing per unit time ✓
  • C. resistance per unit length
  • D. heat produced per unit resistance
Answer: B. charge flowing per unit time
Electric current is given by I = Q/t, where Q is charge and t is time.
A charge of 120 C flows through a wire in 60 s. What is the current in the wire?
  • A. 0.5 A
  • B. 1 A
  • C. 2 A ✓
  • D. 4 A
Answer: C. 2 A
Using I = Q/t, current = 120/60 = 2 A.
A 4 Ω resistor and a 6 Ω resistor are connected in series across a 20 V battery. The potential difference across the 6 Ω resistor is:
  • A. 6 V
  • B. 8 V
  • C. 12 V ✓
  • D. 20 V
Answer: C. 12 V
Total resistance = 10 Ω, so current = 20/10 = 2 A. Voltage across 6 Ω resistor = IR = 2 × 6 = 12 V.
Three resistors of 2 Ω, 3 Ω and 6 Ω are connected in parallel across a 6 V battery. The total power supplied by the battery is:
  • A. 6 W
  • B. 12 W
  • C. 24 W
  • D. 36 W ✓
Answer: D. 36 W
For parallel combination, 1/R = 1/2 + 1/3 + 1/6 = 1, so R = 1 Ω. Power = V²/R = 36/1 = 36 W.

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