Chapter Exam

Chapter-8 Mechanical Properties of Solids — Online MCQ Test

Q: What is stress defined as?

Answer: A. Force applied per unit area — Stress is the restoring force per unit area acting on a body when it is deformed.

Q: A wire of length L and cross-sectional area A is stretched by a force F. Its Young's modulus can be calculated using:

Answer: A. Y = (F × L) / (A × ΔL) — Young's modulus Y = Stress/Strain = (F/A)/(ΔL/L) = (F × L)/(A × ΔL).

Q: The relationship between Young's modulus (Y), bulk modulus (K), and shear modulus (G) is given by:

Answer: B. Y = 9KG / (3K + G) — The relationship Y = 9KG/(3K + G) connects the three elastic moduli for isotropic materials.

Q: A steel wire of diameter 2 mm and length 5 m is stretched by applying a force of 5000 N. If Young's modulus of steel is 2 × 10¹¹ Pa, the extension produced is:

Answer: B. 3.98 mm — Y = (F/A) × (L/ΔL); ΔL = FL/(AY) = (5000 × 5)/(π × 10⁻⁶ × 2 × 10¹¹) ≈ 3.98 × 10⁻³ m = 3.98 mm.

PHYSICS · Grade 11 · CBSE(NCERT)

Practice Chapter-8 Mechanical Properties of Solids with a free chapter-wise online MCQ test for CBSE(NCERT) Grade 11 PHYSICS. This chapter covers: Elastic behavior - Stress-strain relationship - Hooke's law - Young's modulus - Bulk modulus - Shear modulus - Poisson's ratio - Elastic potential energy. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-8 Mechanical Properties of Solids — Important Questions & Answers (FAQ)

Frequently asked questions from CBSE(NCERT) Grade 11 PHYSICS — Chapter-8 Mechanical Properties of Solids, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is stress defined as?

A. Force applied per unit area ✓
B. Change in length per unit original length
C. Deformation produced in a body
D. Energy stored in a deformed body

Answer: A. Force applied per unit area
Stress is the restoring force per unit area acting on a body when it is deformed.

Strain is a dimensionless quantity because it represents:

A. Force per unit area
B. Ratio of change in dimension to original dimension ✓
C. Energy per unit volume
D. Deformation in a body

Answer: B. Ratio of change in dimension to original dimension
Strain is the ratio of change in dimension to the original dimension, making it a dimensionless quantity.

A wire of length L and cross-sectional area A is stretched by a force F. Its Young's modulus can be calculated using:

A. Y = (F × L) / (A × ΔL) ✓
B. Y = (F × ΔL) / (A × L)
C. Y = F / (A × L)
D. Y = (A × L) / (F × ΔL)

Answer: A. Y = (F × L) / (A × ΔL)
Young's modulus Y = Stress/Strain = (F/A)/(ΔL/L) = (F × L)/(A × ΔL).

The relationship between Young's modulus (Y), bulk modulus (K), and shear modulus (G) is given by:

A. Y = 3KG / (3K + G)
B. Y = 9KG / (3K + G) ✓
C. K = YG / (3Y - 6G)
D. G = 3YK / (9K + Y)

Answer: B. Y = 9KG / (3K + G)
The relationship Y = 9KG/(3K + G) connects the three elastic moduli for isotropic materials.

A steel wire of diameter 2 mm and length 5 m is stretched by applying a force of 5000 N. If Young's modulus of steel is 2 × 10¹¹ Pa, the extension produced is: