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Chapter-14 Electricity — Online MCQ Test

PHYSICS · Grade 10 · IGCSE cambridge

Practice Chapter-14 Electricity with a free chapter-wise online MCQ test for IGCSE cambridge Grade 10 PHYSICS. This chapter covers: Static electricity current voltage resistance series and parallel circuits and electrical safety.. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-14 Electricity — Important Questions & Answers (FAQ)

Frequently asked questions from IGCSE cambridge Grade 10 PHYSICS — Chapter-14 Electricity, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the SI unit of electric current?
  • A. Ampere (A) ✓
  • B. Volt (V)
  • C. Ohm (Ω)
  • D. Coulomb (C)
Answer: A. Ampere (A)
The ampere is the SI unit of electric current, defined as the flow of charge per unit time.
Static electricity is caused by the transfer of _____ between objects.
  • A. protons
  • B. electrons ✓
  • C. neutrons
  • D. ions
Answer: B. electrons
Static electricity results from the accumulation of electrons (or loss of electrons) on an object's surface due to friction or contact.
In a series circuit, how does the current behave as it passes through multiple resistors?
  • A. The current increases at each resistor
  • B. The current remains the same throughout the circuit ✓
  • C. The current decreases at each resistor
  • D. The current splits equally among resistors
Answer: B. The current remains the same throughout the circuit
In a series circuit, current is the same at all points because charge cannot accumulate or be lost; it flows sequentially through each component.
A circuit contains two resistors: R₁ = 6Ω in series with a parallel combination of R₂ = 3Ω and R₃ = 6Ω. What is the total resistance of the circuit?
  • A. 15Ω
  • B. 8Ω ✓
  • C. 9Ω
  • D. 12Ω
Answer: B. 8Ω
Parallel resistance of R₂ and R₃: 1/R_p = 1/3 + 1/6 = 3/6, so R_p = 2Ω. Total = R₁ + R_p = 6 + 2 = 8Ω.
A heating element has a resistance of 20Ω. When connected to a 240V supply, it operates normally. However, if due to a fault the resistance suddenly increases to 30Ω at the same voltage, and the circuit has a 20A circuit breaker, which of the following correctly describes the outcome?
  • A. The current increases, exceeding 20A, and the circuit breaker trips
  • B. The current decreases to 8A, the breaker does not trip, but heating reduces ✓
  • C. The current increases to 30A, causing the breaker to trip
  • D. The current remains constant due to the constant voltage supply
Answer: B. The current decreases to 8A, the breaker does not trip, but heating reduces
With R = 30Ω and V = 240V, current I = 240/30 = 8A, which is below the 20A limit. The breaker does not trip, but power output decreases from P = V²/R.

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