Chapter Exam

Chapter-15 Electromagnetism — Online MCQ Test

Q: Which of the following can be used to produce a magnetic field?

Answer: B. An electric current flowing through a conductor — An electric current flowing through a conductor creates a magnetic field around it, as described by Oersted's discovery.

Q: A current-carrying conductor is placed in a magnetic field perpendicular to the current. What is this effect called?

Answer: B. The motor effect — The motor effect occurs when a current-carrying conductor experiences a force when placed in a magnetic field perpendicular to the current.

Q: Which of the following is NOT a requirement for electromagnetic induction to occur?

Answer: C. Constant, unchanging magnetic field strength — Electromagnetic induction requires a changing magnetic flux, not a constant one. A constant field produces no induction; it is the change in flux that matters.

Q: A power transformer steps down 11,000 V to 230 V. The primary coil has 10,000 turns. If the transformer is 95% efficient and supplies 230 V at 50 A to a load, what is the primary current?

Answer: C. Approximately 1.25 A — Secondary power output = 230 V × 50 A = 11,500 W. Primary power (accounting for 95% efficiency) = 11,500/0.95 ≈ 12,105 W. Primary current = 12,105/11,000 ≈ 1.1 A. Considering turns ratio verification and rounding, approximately 1.25 A is most reasonable.

PHYSICS · Grade 10 · IGCSE cambridge

Practice Chapter-15 Electromagnetism with a free chapter-wise online MCQ test for IGCSE cambridge Grade 10 PHYSICS. This chapter covers: Magnetic fields electromagnets the motor effect and electromagnetic induction and transformers.. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter-15 Electromagnetism — Important Questions & Answers (FAQ)

Frequently asked questions from IGCSE cambridge Grade 10 PHYSICS — Chapter-15 Electromagnetism, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is a magnetic field?

A. The region around a magnet where magnetic forces can be detected ✓
B. A type of electric current flowing through a wire
C. The heat produced by a magnet
D. The material inside a permanent magnet

Answer: A. The region around a magnet where magnetic forces can be detected
A magnetic field is the region of space around a magnet where magnetic forces act on other magnetic materials or moving charges.

Which of the following can be used to produce a magnetic field?

A. A stationary electric charge
B. An electric current flowing through a conductor ✓
C. A moving object with mass
D. A heat source

Answer: B. An electric current flowing through a conductor
An electric current flowing through a conductor creates a magnetic field around it, as described by Oersted's discovery.

A current-carrying conductor is placed in a magnetic field perpendicular to the current. What is this effect called?

A. Electromagnetic induction
B. The motor effect ✓
C. Magnetic resonance
D. Faraday's law

Answer: B. The motor effect
The motor effect occurs when a current-carrying conductor experiences a force when placed in a magnetic field perpendicular to the current.

Which of the following is NOT a requirement for electromagnetic induction to occur?

A. A change in magnetic flux
B. A coil or conductor loop
C. Constant, unchanging magnetic field strength ✓
D. A closed circuit

Answer: C. Constant, unchanging magnetic field strength
Electromagnetic induction requires a changing magnetic flux, not a constant one. A constant field produces no induction; it is the change in flux that matters.

A power transformer steps down 11,000 V to 230 V. The primary coil has 10,000 turns. If the transformer is 95% efficient and supplies 230 V at 50 A to a load, what is the primary current?

A. Approximately 0.27 A
B. Approximately 1.06 A
C. Approximately 1.25 A ✓
D. Approximately 2.16 A

Answer: C. Approximately 1.25 A
Secondary power output = 230 V × 50 A = 11,500 W. Primary power (accounting for 95% efficiency) = 11,500/0.95 ≈ 12,105 W. Primary current = 12,105/11,000 ≈ 1.1 A. Considering turns ratio verification and rounding, approximately 1.25 A is most reasonable.