- A. More abundant species will exclude the less abundant species through competition.
- B. Competition for the same resources excludes species having different food preferences.
- C. No two species can occupy the same niche indefinitely for the same limited resources.
- D. Larger organisms exclude smaller ones through competition.
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Log in to view solution →- A. Hydrogen bonds
- B. Phosphodiester bond
- C. Covalent bond
- D. Disulphide bridges
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Log in to view solution →- A. Endocarp
- B. Fleshy mesocarp
- C. Free nuclear proembryo
- D. Free nuclear endosperm
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Log in to view solution →- A. Endocarp
- B. Fleshy mesocarp
- C. Free nuclear proembryo
- D. Free nuclear endosperm
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Log in to view solution →- A. They lack a protein coat
- B. They are smaller than viruses
- C. They cause infections
- D. Their RNA is of high molecular weight
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Log in to view solution →- A. Chitinous exoskeleton
- B. Metameric segmentation
- C. Parapodia
- D. Jointed appendages
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Log in to view solution →- A. Recessive gene disorder
- B. X-linked recessive gene disorder
- C. Chromosomal disorder
- D. Dominant gene disorder
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Log in to view solution →- A. Photophosphorylation and non-cyclic electron transport
- B. Two photosystems operating simultaneously
- C. Photophosphorylation and cyclic electron transport
- D. Oxidative phosphorylation
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Log in to view solution →- A. Emphysema
- B. Asthma
- C. Respiratory acidosis
- D. Respiratory alkalosis
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Log in to view solution →- A. Emphysema
- B. Asthma
- C. Respiratory acidosis
- D. Respiratory alkalosis
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Log in to view solution →- A. Ley farming
- B. Contour farming
- C. Strip farming
- D. Shifting agriculture
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Log in to view solution →- A. Both (a) and (b) are correct
- B. (b) is true but (a) is false
- C. (a) is true but (b) is false
- D. Both (a) and (b) are false
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Log in to view solution →- A. It is usually done when a woman is between 14-16 weeks pregnant.
- B. It is used for prenatal sex determination
- C. It can be used for detection of Down syndrome
- D. It can be used for detection of Cleft palate
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Log in to view solution →- A. Stroma
- B. Lumen of thylakoids
- C. Inter membrane space
- D. Antennae complex
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Log in to view solution →- A. Guanosine and Retinol
- B. Opsin and Retinal
- C. Opsin and Retinol
- D. Transducin and Retinene
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Log in to view solution →- A. Telomere of the chromosome
- B. Kinetochore of the chromosome
- C. Centromere of the chromosome
- D. Kinetosome of the chromosome
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Log in to view solution →- A. Telomere of the chromosome
- B. Kinetochore of the chromosome
- C. Centromere of the chromosome
- D. Kinetosome of the chromosome
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Log in to view solution →- A. Gangetic shark
- B. River dolphin
- C. Blue whale
- D. Seahorse
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Log in to view solution →- A. Glucose
- B. Galactose
- C. Lactose
- D. Lactose and galactose
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Log in to view solution →- A. Parathormone – Calcitonin
- B. Insulin – Glucagon
- C. Aldosterone – Atrial Natriuretic Factor
- D. Relaxin – Inhibin
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Log in to view solution →- A. Cilia, Flagella and Peroxisomes
- B. Spindle fibres, Centrioles and Cilia
- C. Centrioles, Spindle fibres and Chromatin
- D. Centrosome, Nucleosome and Centrioles
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Log in to view solution →- A. Polysome
- B. Polymer
- C. Polypeptide
- D. Okazaki fragment
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Log in to view solution →- A. the sperms are transported into vagina just after the release of ovum in fallopian tube
- B. the ovum and sperms are transported simultaneously to ampullary isthmic junction of the fallopian tube
- C. the ovum and sperms are transported simultaneously to ampullary - isthmic junction of the cervix
- D. the sperms are transported into cervix within 48 hrs of release of ovum in uterus
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Log in to view solution →- A. the sperms are transported into vagina just after the release of ovum in fallopian tube
- B. the ovum and sperms are transported simultaneously to ampullary isthmic junction of the fallopian tube
- C. the ovum and sperms are transported simultaneously to ampullary-isthmic junction of the cervix
- D. the sperms are transported into cervix within 48 hrs of release of ovum in uterus
Correct answer & explanation hidden
Log in to view solution →- A. bacterial infection of the lungs
- B. allergic reaction of the mast cells in the lungs
- C. inflammation of the trachea
- D. accumulation of fluid in the lungs
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Log in to view solution →- A. ABA
- B. GA3
- C. IAA
- D. Ethylene
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Log in to view solution →- A. Carina
- B. Pappus
- C. Vexillum
- D. Corona
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Log in to view solution →- A. Liliaceae
- B. Solanaceae
- C. Fabaceae
- D. Poaceae
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Log in to view solution →- A. Chitin
- B. Peptidoglycan
- C. Cellulose
- D. Hemicellulose
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Log in to view solution →- A. FSH stimulates the sertoli cells which help in spermiogenesis
- B. LH triggers ovulation in ovary
- C. LH and FSH decrease gradually during the follicular phase
- D. LH triggers secretion of androgens from the Leydig cells
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Log in to view solution →- A. FSH stimulates the sertoli cells which help in spermiogenesis
- B. LH triggers ovulation in ovary
- C. LH and FSH decrease gradually during the follicular phase
- D. LH triggers secretion of androgens from the Leydig cells
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Log in to view solution →- A. sqrt(gR)
- B. sqrt(2gR)
- C. sqrt(3gR)
- D. sqrt(5gR)
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Log in to view solution →- A. Pachytene
- B. Leptotene
- C. Zygotene
- D. Diplotene
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Log in to view solution →- A. 4λ
- B. 5λ
- C. 5/2λ
- D. 3λ
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Log in to view solution →- A. 1 : 2 : 1 :: Tall homozygous : Tall heterozygous : Dwarf
- B. 1 : 2 : 1 :: Tall heterozygous : Tall homozygous : Dwarf
- C. 3 : 1 :: Tall : Dwarf
- D. 3 : 1 :: Dwarf : Tall
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Log in to view solution →- A. Compressing the gas isothermally will require more work to be done.
- B. Compressing the gas through adiabatic process will require more work to be done.
- C. Compressing the gas isothermally or adiabatically will require the same amount of work.
- D. Which of the case (whether compression through isothermal or through adiabatic process) requires more work will depend upon the atomicity of the gas.
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Log in to view solution →- A. Over – exploitation
- B. Alien species invasion
- C. Habitat loss and fragmentation
- D. Co-extinctions
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Log in to view solution →- A. 5 : 1
- B. 5 : 4
- C. 3 : 4
- D. 3 : 2
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Log in to view solution →- A. Absence of soil organisms
- B. Least genetic diversity
- C. Absence of weeds
- D. Ecological succession
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Log in to view solution →- A. 37.3 cm
- B. 46.0 cm
- C. 50.0 cm
- D. 54.0 cm
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Log in to view solution →- A. estrogen and progesterone
- B. estrogen and inhibin
- C. progesterone only
- D. progesterone and inhibin
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Log in to view solution →- A. {1 + (n + 1)p}ρ
- B. {2 + (n + 1)p}ρ
- C. {2 + (n - 1)p}ρ
- D. {1 + (n - 1)p}ρ
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Log in to view solution →- A. {1 + (n + 1)p}ρ
- B. {2 + (n + 1)p}ρ
- C. {2 + (n − 1)p}ρ
- D. {1 + (n − 1)p}ρ
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Log in to view solution →- A. Independent replication
- B. Circular structure
- C. Transferable
- D. Single - stranded
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Log in to view solution →- A. Independent replication
- B. Circular structure
- C. Transferable
- D. Single - stranded
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Log in to view solution →- A. A = 0, B = 1, C = 0
- B. A = 1, B = 0, C = 0
- C. A = 1, B = 1, C = 0
- D. A = 1, B = 0, C = 1
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Log in to view solution →- A. Schizocoelom as body cavity
- B. Indeterminate and radial cleavage during embryonic development
- C. Exoskeleton composed of N-acetylglucosamine
- D. Metamerically segmented body
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Log in to view solution →- A. 34 km
- B. 544 km
- C. 136 km
- D. 68 km
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Log in to view solution →- A. Allergic response
- B. Graft rejection
- C. Auto-immune disease
- D. Active immunity
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Log in to view solution →- A. 1 : 2
- B. 1 : 2√2
- C. 1 : 4
- D. 1 : √2
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Log in to view solution →- A. (1) (ii) (ii) (i) (iii)
- B. (2) (ii) (ii) (iv) (iii)
- C. (3) (iv) (iii) (ii) (iv)
- D. (4) (iv) (iii) (i) (ii)
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Log in to view solution →- A. 0°
- B. 90°
- C. 45°
- D. 180°
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Log in to view solution →- A. 1960 s
- B. 1970 s
- C. 1980 s
- D. 1990 s
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Log in to view solution →- A. 0.025 × 10^4 m⁻¹
- B. 0.5 × 10^7 m⁻¹
- C. 0.25 × 10^7 m⁻¹
- D. 2.5 × 10^7 m⁻¹
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Log in to view solution →- A. (a) and (d) are correct
- B. (b) and (d) are correct
- C. (a), (c) and (d) are correct
- D. (a), (b) and (c) are correct
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Log in to view solution →- A. (1) (a) and (d) are correct
- B. (2) (b) and (d) are correct
- C. (3) (a), (c) and (d) are correct
- D. (4) (a), (b) and (c) are correct
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Log in to view solution →- A. (2t² + 3t³) W
- B. (2t² + 4t⁴) W
- C. (2t³ + 3t⁴) W
- D. (2t³ + 3t⁵) W
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Log in to view solution →- A. (2t² + 3t³) W
- B. (2t² + 4t⁴) W
- C. (2t³ + 3t⁴) W
- D. (2t³ + 3t⁵) W
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Log in to view solution →- A. (1) Cyanobacteria are also called blue-green algae
- B. (2) Golden algae are also called desmids
- C. (3) Eubacteria are also called false bacteria.
- D. (4) Phycomycetes are also called algal fungi
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Log in to view solution →- A. 0.51 W
- B. 0.67 W
- C. 0.76 W
- D. 0.89 W
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Log in to view solution →- A. (1) Anther
- B. (2) Connective
- C. (3) Placenta
- D. (4) Thalamus or petal
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Log in to view solution →- A. 3/2 A + 7/3 B
- B. 3A + 7B
- C. 3/2 A + 7/3 B
- D. 2/3 A + 3/2 B
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Log in to view solution →- A. (1) Barrier methods - Prevent fertilization
- B. (2) Intrauterine devices - Increase phagocytosis of sperms, suppress sperm motility and fertilizing capacity of sperms
- C. (3) Hormonal contraceptives - Prevent/retard entry of sperms, prevent ovulation and fertilization
- D. (4) Vasectomy - Prevents spermatogenesis
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Log in to view solution →- A. 4 H
- B. 3 H
- C. 2 H
- D. 1 H
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Log in to view solution →- A. (1) Thermus aquaticus
- B. (2) Thiobacillus ferrooxidans
- C. (3) Bacillus subtilis
- D. (4) Pseudomonas putida
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Log in to view solution →- A. Current I(t) lags voltage V(t) by 90°
- B. Over a full cycle the capacitor C does not consume any energy from the voltage source
- C. Current I(t) is in phase with voltage V(t).
- D. Current I(t) leads voltage V(t) by 180°
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Log in to view solution →- A. (1) Inhibits the secretion of LH, FSH and Prolactin.
- B. (2) Is produced by granulosa cells in ovary and inhibits the secretion of FSH.
- C. (3) Is produced by granulosa cells in ovary and inhibits the secretion of LH.
- D. (4) Is produced by nurse cells in testes and inhibits the secretion of LH.
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Log in to view solution →- A. A → b and c; B→ b and c; C→ b and d; D→ a and d
- B. A → a and c; B→ a and d; D→ a and b; D→ c and d
- C. A → a and d; B→ b and c; C→ b and d; D→ b and c
- D. A → c and d; B→ b and d; C→ b and c; D→ a and d
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Log in to view solution →- A. (1) Flower
- B. (2) Leaf
- C. (3) Stem
- D. (4) Root
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Log in to view solution →- A. Flower
- B. Leaf
- C. Stem
- D. Root
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Log in to view solution →- A. sqrt(gR * (μs + tanθ) / (1 - μs tanθ))
- B. sqrt(gR * (μs + tanθ) / (1 - μs tanθ))
- C. gR * (μs + tanθ) / (1 - μs tanθ)
- D. sqrt(gR * (tanθ - μs) / (1 + μs tanθ))
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Log in to view solution →- A. sqrt(gR(μs + tan θ) / (1 - μs tan θ))
- B. sqrt(gR(μs + tan θ) / (1 - μs tan θ))
- C. sqrt(gR(μs + tan θ) / (1 - μs tan θ))
- D. sqrt(gR(μs + tan θ) / (1 - μs tan θ))
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Log in to view solution →- A. (1) Activated pathogens
- B. (2) Harvested antibodies
- C. (3) Gamma globulin
- D. (4) Attenuated pathogens
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Log in to view solution →- A. Activated pathogens
- B. Harvested antibodies
- C. Gamma globulin
- D. Attenuated pathogens
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Log in to view solution →- A. Mitochondria
- B. Chloroplasts
- C. Lysosomes
- D. Nuclei
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Log in to view solution →- A. Spasm
- B. Fatigue
- C. Tetanus
- D. Tonus
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Log in to view solution →- A. Pitcher of Nepenthes
- B. Thorns of citrus
- C. Tendrils of cucumber
- D. Flattened structures of Opuntia
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Log in to view solution →- A. Xanthophylls
- B. Chlorophylls
- C. Carotenoids
- D. Anthocyanins
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Log in to view solution →- A. Gymnosperms are both homosporous and heterosporous
- B. Salvinia, Ginkgo and Pinus all are gymnosperms
- C. Sequoia is one of the tallest trees
- D. The leaves of gymnosperms are not well adapted to extremes of climate
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Log in to view solution →- A. Polymerase chain reaction
- B. Zinc finger analysis
- C. Restriction enzymes
- D. DNA–DNA hybridization
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Log in to view solution →- A. Polymerase chain reaction
- B. Zinc finger analysis
- C. Restriction enzymes
- D. DNA–DNA hybridization
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Log in to view solution →- A. Smooth muscle - Wall of intestine
- B. Areolar tissue - Tendons
- C. Transitional epithelium - Tip of nose
- D. Cuboidal epithelium - Lining of stomach
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Log in to view solution →- A. Smooth muscle : Wall of intestine
- B. Areolar tissue : Tendons
- C. Transitional epithelium : Tip of nose
- D. Cuboidal epithelium : Lining of stomach
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Log in to view solution →- A. C3
- B. C4
- C. CAM
- D. Nitrogen fixer
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Log in to view solution →- A. Dorsal fin of a Shark
- B. Wing of a Moth
- C. Hind limb of Rabbit
- D. Flipper of Whale
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Log in to view solution →- A. Cartilaginous endoskeleton - Chondrichthyes
- B. Viviparous - Mammalia
- C. Possess a mouth with an upper and a lower jaw - Chordata
- D. 3 - chambered heart with one incompletely divided ventricle - Reptilia
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Log in to view solution →- A. Mutations in proto-oncogenes accelerate the cell cycle.
- B. Mutations destroy telomerase inhibitors.
- C. Mutations inactivate the cell control.
- D. Mutations inhibit production of telomerase.
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Log in to view solution →- A. Melatonin and Serotonin
- B. Thyroxine and Triiodothyronine
- C. Estrogen and Progesterone
- D. Cortisol and Cortisone
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Log in to view solution →- A. Melatonin and Serotonin
- B. Thyroxine and Triiodothyronine
- C. Estrogen and Progesterone
- D. Cortisol and Cortisone
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Log in to view solution →- A. (a) is correct but (b) is false.
- B. (b) is correct but (a) is false.
- C. Both (a) and (b) are correct.
- D. Both (a) and (b) are false.
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Log in to view solution →- A. reduce the rate of heartbeat.
- B. reduce the blood supply to the brain.
- C. decrease the affinity of haemoglobin with oxygen.
- D. release bicarbonate ions by the liver.
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Log in to view solution →- A. Divergent evolution
- B. Convergent evolution
- C. Shared ancestry
- D. Stabilizing selection
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Log in to view solution →- A. Hind II
- B. Protease
- C. DNase I
- D. RNase
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Log in to view solution →- A. E.P. Odum
- B. A.G. Tansley
- C. E. Haeckel
- D. E. Warming
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Log in to view solution →- A. E.P. Odum
- B. A.G. Tansley
- C. E. Haeckel
- D. E. Warming
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Log in to view solution →- A. Sucrose is a disaccharide.
- B. Cellulose is a polysaccharide.
- C. Uracil is a pyrimidine.
- D. Glycine is a sulphur containing amino acid.
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Log in to view solution →- A. Sucrose is a disaccharide.
- B. Cellulose is a polysaccharide.
- C. Uracil is a pyrimidine.
- D. Glycine is a sulphur containing amino acid.
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Log in to view solution →- A. Wind
- B. Insects
- C. Birds
- D. Water
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Log in to view solution →- A. when N/K is exactly one.
- B. when N nears the carrying capacity of the habitat.
- C. when N/K equals zero.
- D. when the death rate is greater than the birth rate.
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Log in to view solution →- A. Tapetum helps in the dehiscence of anther
- B. Exine of pollen grains is made up of sporopollenin
- C. Pollen grains of many species cause severe allergies
- D. Stored pollen in liquid nitrogen can be used in the crop breeding programmes
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Log in to view solution →- A. Lichens
- B. Liverworts
- C. Mosses
- D. Green algae
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Log in to view solution →- A. AUG
- B. UGA
- C. UAA
- D. UAG
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Log in to view solution →- A. Ossified endoskeleton
- B. Breathing using lungs
- C. Viviparity
- D. Warm blooded nature
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Log in to view solution →- A. Ossified endoskeleton
- B. Breathing using lungs
- C. Viviparity
- D. Warm blooded nature
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Log in to view solution →- A. Biological names can be written in any language
- B. The first word in a biological name represents the genus name, and the second is a specific epithet
- C. The names are written in Latin and are italicised
- D. When written by hand, the names are to be underlined
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Log in to view solution →- A. same as that in the aorta.
- B. more than that in the carotid.
- C. more than that in the pulmonary vein.
- D. less than that in the vena cavae.
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Log in to view solution →- A. plumule
- B. coleorhiza
- C. coleoptile
- D. scutellum
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Log in to view solution →- A. gastrin secreting cells
- B. parietal cells
- C. peptic cells
- D. acidic cells
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Log in to view solution →- A. Nitrous oxide
- B. Ozone
- C. Ammonia
- D. Methane
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Log in to view solution →- A. Monera
- B. Protista
- C. Fungi
- D. Animalia
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Log in to view solution →- A. Both processes cannot happen simultaneously.
- B. Both processes can happen together because the diffusion coefficient of water and CO2 is different.
- C. The above processes happen only during night-time.
- D. One process occurs during daytime, and the other at night.
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Log in to view solution →- A. Renal Vein
- B. Dorsal Aorta
- C. Hepatic Vein
- D. Hepatic Portal Vein
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Log in to view solution →- A. Sporulation
- B. Budding
- C. Somatic hybridization
- D. Apomixis
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Log in to view solution →- A. Trichoderma polysporum : Cyclosporine A : Immunosuppressive drug
- B. Monascus purpureus : Statins : Lowering of blood cholesterol
- C. Streptococcus : Streptokinase : Removal of clot from blood vessel
- D. Clostridium butylicum : Lipase : Removal of oil stains
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Log in to view solution →- A. The two genes are located on two different chromosomes.
- B. Chromosomes failed to separate during meiosis.
- C. The two genes are linked and present on the same chromosome.
- D. Both of the characters are controlled by more than one gene.
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Log in to view solution →- A. It is easier to carry a small body weight.
- B. Smaller animals have a higher metabolic rate.
- C. Small animals have a lower O2 requirement.
- D. The efficiency of muscles in large animals is less than in small animals.
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Log in to view solution →- A. Spindle fibres
- B. Disappearance of nucleolus
- C. Chromosome movement
- D. Synapsis
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Log in to view solution →- A. Pollen grains of many species can germinate on the stigma of a flower, but only one pollen tube of the same species grows into the style.
- B. Insects that consume pollen or nectar without bringing about pollination are called pollen/nectar robbers.
- C. Pollen germination and pollen tube growth are regulated by chemical components of pollen interacting with those of the pistil.
- D. Some reptiles have also been reported as pollinators in some plant species.
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Log in to view solution →- A. Complementary cells
- B. Subsidiary cells
- C. Bulliform cells
- D. Lenticels
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Log in to view solution →- A. Semilunar valve
- B. Ileocaecal valve
- C. Pyloric sphincter
- D. Sphincter of Oddi
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Log in to view solution →- A. Cladodes
- B. Phyllodes
- C. Phylloclades
- D. Scales
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Log in to view solution →- A. Cladodes
- B. Phyllodes
- C. Phylloclades
- D. Scales
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Log in to view solution →- A. Halophiles
- B. Thermoacidophiles
- C. Methanogens
- D. Eubacteria
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Log in to view solution →- A. Halophiles
- B. Thermoacidophiles
- C. Methanogens
- D. Eubacteria
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Log in to view solution →- A. Drying of the river very soon due to algal bloom.
- B. Increased population of aquatic food web organisms.
- C. An increased production of fish due to biodegradable nutrients.
- D. Death of fish due to lack of oxygen.
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Log in to view solution →- A. Aneuploidy
- B. Polyploidy
- C. Somaclonal variation
- D. Polyteny
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Log in to view solution →- A. Three glycerol molecules and one fatty acid molecule
- B. One glycerol and three fatty acid molecules
- C. One glycerol and one fatty acid molecule
- D. Three glycerol and three fatty acid molecules
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Log in to view solution →- A. C + 2H2SO4 → CO2 + 2SO2 + 2H2O
- B. CaF2 + H2SO4 → CaSO4 + 2HF
- C. Cu + 2H2SO4 → CuSO4 + SO2 + 2H2O
- D. 3S + 2H2SO4 → 3SO2 + 2H2O
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Log in to view solution →- A. dz^2, dx^2-y^2
- B. dxy, dx^2-y^2
- C. dxz, dz^2
- D. dxz, dyz
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Log in to view solution →- A. Planar triangle, sp3d3
- B. Square planar, sp3d2
- C. Octahedral, sp3d2
- D. Trigonal bipyramidal, sp3d
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Log in to view solution →- A. SeF4 and CH4 have same shape
- B. I3+ has bent geometry
- C. PH5 and BiCl5 do not exist
- D. pπ-dπ bonds are present in SO2
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Log in to view solution →- A. Br- > CN- > NH3 > C6H5-
- B. CN- > Br- > C6H5- > NH3
- C. NH3 > CN- > Br- > C6H5-
- D. CN- > C6H5- > Br- > NH3
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Log in to view solution →- A. All the lanthanons are much more reactive than aluminium
- B. Ce(+4) solutions are widely used as oxidizing agent in volumetric analysis
- C. Europium shows +2 oxidation state.
- D. The basicity decreases as the ionic radius decreases from Pr to Lu.
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Log in to view solution →- A. d4
- B. d9
- C. d7
- D. d8
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Log in to view solution →- A. Chloroethene
- B. Isopropyl chloride
- C. Chlorobenzene
- D. Bromobenzene
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Log in to view solution →- A. 2 and 4
- B. 2 and 5
- C. 2 and 3
- D. 3 and 4
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Log in to view solution →- A. Primary (1°) nitro compound
- B. Secondary (2°) nitro compound
- C. Primary amine
- D. Secondary amine
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Log in to view solution →- A. DNA → RNA → Proteins
- B. DNA → RNA → Carbohydrates
- C. Amino acids → Proteins → DNA
- D. DNA → Carbohydrates → Proteins
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Log in to view solution →- A. L-erythrose, L-threose, D-erythrose, D-threose
- B. D-erythrose, D-threose, L-erythrose, L-threose
- C. L-erythrose, L-threose, L-erythrose, D-threose
- D. D-threose, D-erythrose, L-threose, L-erythrose
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Log in to view solution →- A. Structure 1
- B. Structure 2
- C. Structure 3
- D. Structure 4
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Log in to view solution →- A. N, N’-dimethylformamide (DMF)
- B. Water
- C. Ethanol
- D. Methanol
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Log in to view solution →- A. Both I and II
- B. Both II and III
- C. III only
- D. Both I and III
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Log in to view solution →- A. III > II > I
- B. II > I > III
- C. I > II > III
- D. II > III > I
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Log in to view solution →- A. C4H10
- B. C2H4
- C. C3H6
- D. C2H2
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Log in to view solution →- A. Cellulose
- B. Concentrated acetic acid
- C. H2O2
- D. HCN
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Log in to view solution →- A. 0.086 S cm2/mol
- B. 28.8 S cm2/mol
- C. 2.88 S cm2/mol
- D. 11.52 S cm2/mol
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Log in to view solution →- A. Rate is independent of the surface coverage
- B. Rate of decomposition is very slow
- C. Rate is proportional to the surface coverage
- D. Rate is inversely proportional to the surface coverage
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Log in to view solution →- A. Rate is independent of the surface coverage
- B. Rate of decomposition is very slow
- C. Rate is proportional to the surface coverage
- D. Rate is inversely proportional to the surface coverage
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Log in to view solution →- A. III > II > I
- B. III > I > II
- C. I > II > III
- D. II > I > III
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Log in to view solution →- A. 220 minutes
- B. 330 minutes
- C. 55 minutes
- D. 110 minutes
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Log in to view solution →- A. 10
- B. 14
- C. 2
- D. 6
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Log in to view solution →- A. ΔS = nRT ln(pf/pi)
- B. ΔS = RT ln(pi/pf)
- C. ΔS = nR ln(pf/pi)
- D. ΔS = nR ln(pi/pf)
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Log in to view solution →- A. 2
- B. 3
- D. 1
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Log in to view solution →- A. 0.77%
- B. 1.6%
- C. 0.0060%
- D. 0.013%
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Log in to view solution →- A. 8 and 4
- B. 4 and 8
- C. 4 and 2
- D. 6 and 6
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Log in to view solution →- A. ΔG° < 0; Keq > 1
- B. ΔG° < 0; Keq < 1
- C. ΔG° > 0; Keq < 1
- D. ΔG° > 0; Keq > 1
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Log in to view solution →- A. ΔP = Pobserved - Pcalculated by Raoult’s law = 0
- B. ΔGmix = 0
- C. ΔHmix = 0
- D. ΔUmix = 0
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Log in to view solution →- A. 1.6 × 10^-11 M
- B. Zero
- C. 1.26 × 10^-5 M
- D. 1.6 × 10^-9 M
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Log in to view solution →- A. 20, 30
- B. 30, 20
- C. 40, 30
- D. 60, 40
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Log in to view solution →- A. 3.75 × 10^20
- B. 7.48 × 10^23
- C. 6 × 10^23
- D. 6 × 10^20
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Log in to view solution →- A. Accepts OH- from water releasing proton
- B. Combines with proton from water molecule
- C. Contains replaceable H+ ion
- D. Gives up a proton
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Log in to view solution →- A. AlH3
- B. K[AlF3H]
- C. K3[AlF3H3]
- D. K3[AlF6]
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Log in to view solution →- A. Zinc has lower negative electrode potential than iron
- B. Zinc has higher negative electrode potential than iron
- C. Zinc is lighter than iron
- D. Zinc has lower melting point than iron
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Log in to view solution →- A. Milk of lime
- B. Aqueous solution of slaked lime
- C. Limewater
- D. Quicklime
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Log in to view solution →- A. Milk of lime
- B. Aqueous solution of slaked lime
- C. Limewater
- D. Quicklime
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Log in to view solution →- A. sp, sp2 and sp3
- B. sp2, sp and sp3
- C. sp, sp3 and sp2
- D. sp2, sp3 and sp
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Log in to view solution →- A. CF4
- B. SiF4
- C. BF3
- D. PF3
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Log in to view solution →- A. SO3(2-), CO3(2-)
- B. ClO3(-), SO3(2-)
- C. CO3(2-), NO3(-)
- D. ClO3(-), CO3(2-)
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Log in to view solution →- A. Its salts rarely hydrolyze
- B. Its hydride is electron-deficient and polymeric
- C. It is rendered passive by nitric acid
- D. It forms Be2C
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