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Chapter 5: Molecular Basis of Inheritance — Online MCQ Test

BIOLOGY · CLASS 12 INTER II YEAR · Andhra State Board

Practice Chapter 5: Molecular Basis of Inheritance with a free chapter-wise online MCQ test for Andhra State Board CLASS 12 INTER II YEAR BIOLOGY. This chapter covers: DNA RNA DNA Replication Transcription Translation Genetic Code Lac Operon Human Genome Project DNA Fingerprinting Gene Regulation Chromosomes. AI-generated questions from basic to board-exam level, with instant results and explanations.

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Chapter 5: Molecular Basis of Inheritance — Important Questions & Answers (FAQ)

Frequently asked questions from Andhra State Board CLASS 12 INTER II YEAR BIOLOGY — Chapter 5: Molecular Basis of Inheritance, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the primary function of DNA in a cell?
  • A. Storage of genetic information ✓
  • B. Protein synthesis
  • C. Energy production
  • D. Enzyme catalysis
Answer: A. Storage of genetic information
DNA serves as the repository of genetic information that codes for all proteins and traits in an organism.
Which nitrogenous bases are found in DNA?
  • A. Adenine, Guanine, Cytosine, Uracil
  • B. Adenine, Guanine, Cytosine, Thymine ✓
  • C. Adenine, Guanine, Uracil, Thymine
  • D. Adenine, Cytosine, Uracil, Thymine
Answer: B. Adenine, Guanine, Cytosine, Thymine
DNA contains the four bases: Adenine (A), Guanine (G), Cytosine (C), and Thymine (T). Uracil is found in RNA instead.
Which of the following is NOT a step in protein synthesis?
  • A. Transcription
  • B. Translation
  • C. Replication ✓
  • D. None - all are steps
Answer: C. Replication
Protein synthesis involves transcription (DNA to mRNA) and translation (mRNA to protein). DNA replication is a separate process for copying genetic material.
In the genetic code, how many codons code for amino acids?
  • A. 16
  • B. 20
  • C. 61 ✓
  • D. 64
Answer: C. 61
Of the 64 possible codons (4³ combinations), 61 code for the 20 amino acids, and 3 are stop codons that terminate translation.
A scientist observes that in a bacterial mutant, the lac operon is constitutively expressed even in the absence of lactose. Which mutation best explains this observation?
  • A. Mutation in the structural genes (lacZ, lacY, lacA)
  • B. Mutation in the repressor gene resulting in non-functional repressor protein ✓
  • C. Mutation in the promoter making it stronger
  • D. Mutation in the CAP-binding site
Answer: B. Mutation in the repressor gene resulting in non-functional repressor protein
If the repressor protein is non-functional due to mutation, it cannot bind to the operator to block transcription, resulting in continuous expression of the lac genes regardless of lactose presence.

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