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Chapter-7 Alternating Current — Online MCQ Test

PHYSICS · CLASS 12 INTER II YEAR · Andhra State Board

Practice Chapter-7 Alternating Current with a free chapter-wise online MCQ test for Andhra State Board CLASS 12 INTER II YEAR PHYSICS. This chapter covers: AC circuits - RMS value - reactance - impedance - LCR circuit - resonance - transformer - AC generator. AI-generated questions from basic to board-exam level, with instant results and explanations.

10
Questions
20m
Time Limit
3
Attempts Left
  • 10 random questions from this chapter (mixed difficulty)
  • Questions you've seen before won't repeat until the pool resets
  • You have 20 minutes — exam auto-submits when time is up
  • Maximum 3 attempts per chapter
  • Results and explanations shown immediately after submission
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Chapter-7 Alternating Current — Important Questions & Answers (FAQ)

Frequently asked questions from Andhra State Board CLASS 12 INTER II YEAR PHYSICS — Chapter-7 Alternating Current, with answers and explanations. These are sample questions; the exam has its own separate question set.

What is the RMS (root mean square) value of an alternating current with peak value I₀?
  • A. I₀/2
  • B. I₀/√2 ✓
  • C. I₀√2
  • D. 2I₀
Answer: B. I₀/√2
The RMS value of an AC current is defined as I₀/√2, where I₀ is the peak (maximum) value of the current.
Which of the following is the SI unit of reactance?
  • A. Ampere
  • B. Ohm ✓
  • C. Henry
  • D. Farad
Answer: B. Ohm
Reactance (inductive or capacitive) is measured in Ohms (Ω), the same unit as resistance.
A sinusoidal AC voltage is given by V(t) = 230sin(ωt) V. What is its RMS voltage?
  • A. 230 V
  • B. 230/√2 V ≈ 163 V ✓
  • C. 230√2 V ≈ 325 V
  • D. 115 V
Answer: B. 230/√2 V ≈ 163 V
The peak voltage is 230 V, so RMS voltage = 230/√2 ≈ 163 V. The value 230 V used in India is already the RMS value.
In a series RLC circuit, if the inductance is decreased while keeping resistance and capacitance constant, the resonant frequency will:
  • A. Decrease
  • B. Increase ✓
  • C. Remain unchanged
  • D. Become zero
Answer: B. Increase
Resonant frequency f₀ = 1/(2π√LC) is inversely proportional to √L. Decreasing L increases the resonant frequency.
A resonant LCR circuit has R = 5 Ω, L = 10 mH, and the resonant frequency is 1000 Hz. What is the capacitance?
  • A. 2.53 μF ✓
  • B. 25.3 μF
  • C. 0.253 μF
  • D. 253 μF
Answer: A. 2.53 μF
At resonance, f₀ = 1/(2π√LC), so C = 1/(4π²f₀²L) = 1/(4π² × 10⁶ × 0.01) ≈ 2.53 × 10⁻⁶ F = 2.53 μF.

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