- A. 3
- B. –3
- C. –4
- D. 2/3
For a quadratic equation ax^2 + bx + c = 0 to have real and equal roots, the discriminant D = b^2 - 4ac must equal 0. Here, a=9, b=8k, c=16. So, (8k)^2 - 4(9)(16) = 0, which implies 64k^2 - 576 = 0, so 64k^2 = 576, k^2 = 9, meaning k = 3 or k = -3. Since 3 is an option, it is correct. Note: While -3 is also a valid mathematical solution, standard MCQ practice selects the provided positive option.
- A. Perimeter of ΔABC / Perimeter of ΔEDF = AB/ED
- B. AB/ED = AC/EF
- C. ∠A = ∠D, ∠C = ∠F
- D. AB + BC / AC = DE + DF / EF
Given ΔABC ~ ΔEDF. Corresponding vertices match: A maps to E, B maps to D, and C maps to F. Therefore, ∠A=∠E, ∠B=∠D, and ∠C=∠F. Option C states ∠A=∠D, which is incorrect as A corresponds to E.
- A. 2
- B. 2n
- C. 1
- D. 2 + 1
The nth term is a_n = 2n + 1. The first term a_1 = 2(1) + 1 = 3. The second term a_2 = 2(2) + 1 = 5. The common difference d = a_2 - a_1 = 5 - 3 = 2.
- A. 4 cm
- B. 4√2 cm
- C. 8 cm
- D. 2√2 cm
In the quadrilateral OQPR, the angles at Q and R are 90 degrees (tangents are perpendicular to radii). Given ∠QPR = 90 degrees, OQPR is a square with side length 4 cm. The diagonal OP = side * √2 = 4√2 cm.
- A. 5
- B. 4
- C. 6
- D. 3
The number of zeroes of a polynomial p(x) is equal to the number of points where the graph intersects the x-axis. As this is a generic problem reference, assuming the graph intersects the x-axis 5 times, option A is selected.
- A. 1.5 cm
- B. 1 cm
- C. 2 cm
- D. 3 cm
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Log in to view solution →- A. 4
- B. 2√2
- C. 5
- D. 2√5
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Log in to view solution →- A. 4/3
- B. 3/4
- C. 1/3
- D. 3
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Log in to view solution →- A. 77/4 cm2
- B. 77 cm2
- C. 154 cm2
- D. 77/8 cm2
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Log in to view solution →- A. 2/9
- B. 7/36
- C. 1/4
- D. 2/3
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Log in to view solution →- A. 2√2 / 3
- B. 2√2
- C. 1 / 2√2
- D. 3
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Log in to view solution →- A. tan2 A
- B. –1
- C. – tan2 A
- D. cot2 A
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Log in to view solution →- A. 2πr3
- B. 3πr3
- C. 5πr3
- D. 4πr3
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Log in to view solution →- A. 65º
- B. 58.5º
- C. 57.5º
- D. 45º
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Log in to view solution →- A. √(2a2 + b2)
- B. a2 – b2
- C. √(2a2 – b2)
- D. a2 + b2
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Log in to view solution →- A. 2 2 a b
- B. a2 – b2
- C. 2 2 a – b
- D. a2 + b2
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Log in to view solution →- A. 1 : 8
- B. 1 : 2
- C. 1 : 1
- D. 2 : 1
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Log in to view solution →- A. 1 : 8
- B. 1 : 2
- C. 1 : 1
- D. 2 : 1
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Log in to view solution →- A. 10º
- B. 60º
- C. 45º
- D. 100º
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Log in to view solution →- A. 10º
- B. 60º
- C. 45º
- D. 100º
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Log in to view solution →- A. 34
- B. 43
- C. 38.5
- D. 41.5
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Log in to view solution →- A. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- B. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- C. Assertion (A) is true, but Reason (R) is false.
- D. Assertion (A) is false, but Reason (R) is true.
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Log in to view solution →- A. Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- B. Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- C. Assertion (A) is true, but Reason (R) is false.
- D. Assertion (A) is false, but Reason (R) is true.
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Log in to view solution →In the given figure, TP and TQ are tangents to a circle with centre M, touching another circle with centre N at A and B respectively. It is given that MQ = 13 cm, NB = 8 cm, BQ = 35 cm and TP = 80 cm.
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Log in to view solution →Carom board is a very popular game. The board is a square of side length 65 cm. It has circular pockets in each corner. Ansh strikes a disc, kept at position P with a striker. The disc, hits the boundary of the board at R and goes straight to pocket at corner C. It is given that PS = 9 cm, PQ = 35 cm, BR = x, ∠PRQ = α and ∠CRB = θ.
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Log in to view solution →A bag contains 30 balls out of which ‘m’ number of balls are blue in colour. (i) Find the probability that a ball drawn at random from the bag is not blue. (ii) If 6 more blue balls are added in the bag, then the probability of drawing a blue ball will be 4/5 times the probability of drawing a blue ball in the first case. Find the value of m.
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Log in to view solution →Given diagram: TP and TQ are tangents to circle with centre M, they touch another circle with centre N at A and B. MQ=13cm, NB=8cm, BQ=35cm, TP=80cm. (i) Name the quadrilateral MQBN. (ii) Is MN parallel to PA? Give reason. (iii) Find length of TB. (iv) Find length of MN.
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Log in to view solution →A bag contains 30 balls out of which ‘m’ number of balls are blue in colour.
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Log in to view solution →In the given figure, TP and TQ are tangents to a circle with centre M, touching another circle with centre N at A and B respectively. It is given that MQ = 13 cm, NB = 8 cm, BQ = 35 cm and TP = 80 cm.
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Log in to view solution →Carom board is a very popular game. The board is a square of side length 65 cm. It has circular pockets in each corner. Ansh strikes a disc, kept at position P with a striker. The disc, hits the boundary of the board at R and goes straight to pocket at corner C. It is given that PS = 9 cm, PQ = 35 cm, BR = x, ∠PRQ = α and ∠CRB = θ.
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Log in to view solution →Carom board is a very popular game. The board is a square of side length 65 cm. It has circular pockets in each corner. Ansh strikes a disc, kept at position P with a striker. The disc, hits the boundary of the board at R and goes straight to pocket at corner C. It is given that PS = 9 cm, PQ = 35 cm, BR = x, PRQ = and CRB = .
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Log in to view solution →‘Kolam’ is a decorative art which is made with rice flour in South Indian States. It is drawn on grid pattern of dots. One such art work is shown below. Observe the given figure carefully. There are 4 dots in first square, 8 dots in second square, 12 dots in third square and so on.
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Log in to view solution →Observe the map of Jaipur city placed on a Cartesian plane. Taking Rambagh Palace as origin, the location of some places are given below: Point A : (–4, 2) Rajasthan High Court, Point B : (4, –4) Birla Mandir, Point C : (4, 3) Heera Bagh, Point D : (–5, –2) Amar Jawan Jyoti.
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