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Q1
mcq
1 mark
Which of the following curve represents the first order reaction ?
-
A.
(A)
-
B.
(B)
-
C.
(C)
-
D.
(D)
Q2
mcq
1 mark
Which of the following solutions will have the lowest freezing point in water ?
-
A.
0.1 M Glucose
-
B.
0.1 M CaCl2
-
C.
0.1 M KCl
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D.
0.1 M Urea
Q3
mcq
1 mark
Which of the following is not a transition metal ?
Q4
mcq
1 mark
Which of the following represents the fraction of molecules with energies equal to or greater than Ea ?
-
A.
+ Ea/RT
-
B.
e–Ea/RT
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C.
– Ea/RT
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D.
e+Ea/RT
Q5
mcq
1 mark
What will happen during the electrolysis of aqueous solution of CuCl2 by platinum electrodes ?
-
A.
Cu will deposit on anode
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B.
H2 gas will be liberated at cathode
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C.
O2 gas will be liberated at anode
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D.
Cl2 gas will be liberated at anode
Q6
mcq
1 mark
Aspirin is obtained by acetylation of
-
A.
Phenol
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B.
Salicylaldehyde
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C.
2-Hydroxybenzoic acid
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D.
Benzoic acid
Q7
mcq
1 mark
The secondary valency of Co in the complex [Co(NH3)5(NO2)]2+ is
Q8
mcq
1 mark
At low temperature, phenol reacts with dil. HNO3 to yield
-
A.
2, 4, 6-Trinitrophenol
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B.
o-Nitrophenol only
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C.
p-Nitrophenol only
-
D.
ortho-and para-nitrophenol
Q9
mcq
1 mark
Which of the following is ‘not’ true about enantiomers ?
-
A.
They have the same chemical reactivity.
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B.
They have the same specific rotation.
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C.
They have the same melting or boiling point.
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D.
They have the same refractive index.
Q10
mcq
1 mark
Aniline on direct nitration yields
-
A.
51%-ortho, 47%-para, 2%-meta derivatives
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B.
51%-meta, 47%-ortho, 2%-para derivatives
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C.
51%-para, 47%-meta, 2%-ortho derivatives
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D.
51%-ortho, 47%-meta, 2%-para derivatives
Q11
mcq
1 mark
Which of the following amines has lowest pKb value ?
-
A.
C6H5 – N(CH3)2
-
B.
C6H5 – NH(CH3)
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C.
C6H5 – NH2
Q12
mcq
1 mark
The deficiency of which of the following vitamins causes increased fragility of red blood cells and muscular weakness :
-
A.
Vitamin A
-
B.
Vitamin K
-
C.
Vitamin E
-
D.
Vitamin D
Q13
short answer
1 mark
Assertion (A) : It is not possible to separate the components of an azeotrope by fractional distillation. Reason (R) : Components of an azeotrope have the same composition in liquid and vapour phase and boil at a constant temperature.
Q14
short answer
1 mark
Assertion (A) : The presence of –OH group in phenols directs the incoming group to meta position in the ring. Reason (R) : –OH group in phenols activates the aromatic ring towards electrophilic substitution reaction.
Q15
short answer
1 mark
Assertion (A) : Actinoids show wide range of oxidation states. Reason (R) : Actinoids are radioactive in nature.
Q16
short answer
1 mark
Assertion (A) : The pentaacetate of glucose does not react with H2N – OH. Reason (R) : It indicates the presence of free – CHO group in glucose.
Q17
short answer
2 marks
What type of deviation from Raoult’s law is shown by a mixture of phenol and aniline ? Give reason. What will happen to the boiling point of the solution on mixing phenol and aniline ?
Q18
short answer
2 marks
Why are haloarenes less reactive towards nucleophilic substitution reaction ? Give two reasons.
Q19
short answer
2 marks
(a) Write IUPAC names of the following coordination compounds : (i) [Ag(NH3)2] [Ag(CN)2] (ii) K3[Fe(C2O4)3]
Q20
short answer
2 marks
(b) (i) Give a chemical test to show that [Co(NH3)5SO4]Cl and [Co(NH3)5Cl]SO4 are ionisation isomers. (ii) What is meant by the ‘Chelate effect’ ? Give an example.
Q20
short answer
2 marks
Differentiate between the following : (i) Peptide linkage and Glycosidic linkage (ii) Essential amino acids and Non-essential amino acids
Q21
short answer
2 marks
Following reaction takes place in one step : 2A + B — 2C. How will the rate of above reaction change if the volume of the reaction vessel is decreased to one third of its original volume ? Will there be any change in the order of reaction with the reduced volume ?
Q22
short answer
3 marks
For the first order thermal decomposition reaction, following data was obtained : C2H5Cl(g) — C2H4(g) + HCl(g). Calculate rate constant. [Given : log 3 = 0.48]
Q23
short answer
1 mark
[Ag(NH3)2] [Ag(CN)2]
Q24
short answer
1 mark
K3[Fe(C2O4)3]
Q24
short answer
3 marks
Calculate the boiling point of a solution containing 0.61 g of benzoic acid (Molar mass = 122 g mol–1) in 5 g of CS2 in which it dimerises to the extent of 88%. The boiling point and Kb of CS2 are 46.2 C and 2.3 K kg mol–1 respectively.
Q25
short answer
1 mark
Give a chemical test to show that [Co(NH3)5SO4]Cl and [Co(NH3)5Cl]SO4 are ionisation isomers.
Q26
short answer
1 mark
What is meant by the ‘Chelate effect’ ? Give an example.
Q26
short answer
3 marks
Give reasons for the following : (a) Carboxylic acids have higher boiling point than alcohols of comparable molecular masses. (b) Alpha (alpha) hydrogens of aldehydes and ketones are acidic in nature. (c) Nucleophilic addition of ammonia and its derivatives does not occur with carbonyl group in strongly acidic medium.
Q27
short answer
1 mark
Differentiate between the following: Peptide linkage and Glycosidic linkage
Q27
short answer
3 marks
Write the reaction involved in the following : (a) Reimer-Tiemann reaction (b) Kolbe’s reaction (c) Friedal-Crafts acylation of anisole
Q28
short answer
1 mark
Differentiate between the following: Essential amino acids and Non-essential amino acids
Q28
short answer
3 marks
Compound ‘X’ with molecular formula C4H9Br reacts with aqueous KOH to give an alcohol. The rate of this reaction depends only on the concentration of the compound ‘X’. When an optically active isomer ‘Y’ of the compound ‘X’ was treated with aqueous KOH solution, the rate of reaction was found to be dependent on concentration of compound ‘Y’ and aqueous KOH both. (a) Write down the structural formula of both ‘X’ and ‘Y’. (b) Out of ‘X’ and ‘Y’, which one will undergo racemisation and why ? (c) Out of ‘X’ and ‘Y’, which one will form product with inversion of configuration and why ?
Q30
short answer
1 mark
Why is the Equilibrium Constant (Kc) related to Ecell and not to Ecell ?
Q31
short answer
1 mark
Two metals ‘A’ and ‘B’ have standard electrode potential values of –0.24 V and +0.80 V respectively. Which of these will liberate hydrogen gas from dil. H2SO4 ?
Q32
short answer
1 mark
Write the cell reaction which occurs in lead storage battery when it is in charging.
Q33
short answer
3 marks
What type of battery is Mercury cell ? Why it is more advantageous than dry cell ? Write overall reaction taking place in Mercury cell.
Q35
short answer
1 mark
Write the reaction of D-Glucose with HI
Q36
short answer
1 mark
Give reason: Carboxylic acids have higher boiling point than alcohols of comparable molecular masses.
Q37
short answer
1 mark
Give reason: Alpha () hydrogens of aldehydes and ketones are acidic in nature.
Q38
short answer
1 mark
Give reason: Nucleophilic addition of ammonia and its derivatives does not occur with carbonyl group in strongly acidic medium.
Q39
short answer
1 mark
Write the reaction involved in: Reimer-Tiemann reaction
Q40
short answer
1 mark
Write the reaction involved in: Kolbe’s reaction
Q41
short answer
1 mark
Write the reaction involved in: Friedal-Crafts acylation of anisole
Q42
short answer
1 mark
Write down the structural formula of both ‘X’ and ‘Y’ based on C4H9Br reaction with aqueous KOH.
Q43
short answer
1 mark
Out of ‘X’ and ‘Y’, which one will undergo racemisation and why ?
Q44
short answer
1 mark
Out of ‘X’ and ‘Y’, which one will form product with inversion of configuration and why ?
Reading Passage
The reaction of amines with mineral acids to form ammonium salts shows that these are basic in nature. Aliphatic amines are stronger bases than ammonia whereas aromatic amines are weaker bases than ammonia. Aliphatic and aromatic primary and secondary amines react with acid chlorides, anhydrides and esters by nucleophilic substitution reaction. The main problem encountered during electrophilic substitution reactions of aromatic amines is that of their high reactivity. Substitution tends to occur at ortho-and para-positions. Hinsberg reagent is used for the identification and distinction between primary, secondary and tertiary amines. Aryldiazonium salts, usually obtained from arylamines, undergo replacement of the diazonium group with a variety of nucleophiles to provide advantageous methods for producing aryl halides, cyanides, phenols and arenes.
Q48
short answer
2 marks
(i) Why CH3 – NH2 is a stronger base than (CH3)3N in aqueous solution ?
Q49
short answer
1 mark
(ii) Write structural formulae of the compound A and B : CH3CONH2 NaOBr A C6H5COCl Base B
Q50
short answer
1 mark
A compound ‘X’ with molecular formula C3H9N reacts with Hinsberg reagent to give a product insoluble in alkali. Identify ‘X’.
Q51
short answer
1 mark
How can you convert aniline to benzonitrile ?
Q52
short answer
1 mark
Why is –NH2 group of aniline acetylated before carrying out nitration ?
Reading Passage
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometry of coordination compounds. The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields.
Q53
long answer
2 marks
In octahedral crystal field, energies of which d-orbitals will be raised when ligands approach the central metal atom/ion? Give reason in support of your answer.
Q54
short answer
1 mark
Using crystal field theory, write the electronic configuration of central metal atom/ion of the following : (i) [CoF6]3– (ii) [Co(NH3)6]3+ [At. No. : Co = 27]
Q55
short answer
1 mark
[NiCl4]2– is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why? [Atomic No. : Ni = 28]
Q56
short answer
1 mark
Write hybridization and magnetic behaviour of the complex [Fe(CN)6]3–. [Atomic No. : Fe = 26]
Q57
long answer
5 marks
An organic compound (X) has the molecular formula C5H10O. Draw structures for (X) if it : (I) does not give Tollen’s test but gives a positive iodoform test. (II) does not give Tollen’s test and iodoform test but undergoes Aldol condensation. (III) undergoes Cannizzaro’s reaction.
Q58
long answer
5 marks
From the given data of E° values, answer the following questions: (I) Why E° M2+/M show irregular trends? (II) Why E° Cu2+/Cu value is uniquely positive? (III) Why E° Mn2+/Mn value is more negative?
Q59
short answer
Show how each of the following compounds can be converted to benzoic acid : (I) Acetophenone (II) Ethyl benzene
Q60
short answer
1 mark
Draw structure of the 2, 4-dinitrophenyl hyzdrazone derivative of benzaldehyde.
Q61
short answer
1 mark
Arrange the following in increasing order of their reactivity towards HCN : Di-tert. butyl ketone, Acetaldehyde, Acetone
Q62
short answer
1 mark
Give a simple chemical test to distinguish between benzoic acid and ethyl benzoate.
Q63
short answer
1 mark
Write the name of the reagent to convert Ethanenitrile to Ethanal.
Q64
short answer
1 mark
Draw the structure of ‘X’ in the following reaction : CrO3 / 'X'
Q65
short answer
Why E M2+/M show irregular trend in the above values ?
Q66
short answer
Why is E Cu2+/Cu value exceptionally positive ?
Q67
short answer
Why E Mn2+ / Mn value is highly negative ?
Q68
short answer
Write the ionic equations for the oxidising action of potassium permanganate for its reaction with I– in both acidic and alkaline solutions.
Q69
short answer
Name a member of the lanthanoid series (I) which exhibits +4 oxidation state (II) which exhibits +2 oxidation state.
Q70
short answer
Why transition metals act as good catalyst ?
Q71
short answer
Why Cr has higher melting point than Mn ?
Q72
short answer
What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?
Q73
long answer
5 marks
Calculate emf and G for the following cell at 298 K : Mg(s) / Mg2+(0.01 M) // Ag+(0.001 M) / Ag(s) Given : EMg2+ / Mg = –2.37 V EAg+ / Ag = +0.80 V [ 1 F = 96500 C mol–1, log 10 = 1]
Q74
long answer
5 marks
For the reaction : 2AgCl(s) + H2(g) (0.4 atm) — 2Ag(s) + 2H+(0.1 M) + 2Cl–(0.2 M) Calculate emf of the cell at 25 C. Given : G = – 43500 J mol–1 [log 10 = 1, 1 F = 96500 C mol–1]